我的设计使用了斯巴达3E XC35100E设备。我总共可以使用4个多路复用器。然而,尽管使用了3*符号和FFT块(也使用了3个MUX),但设计摘要指定我只使用1个MUX。即使我使用CLB逻辑代替FFT块的MUX,设计摘要也是一样的。
实现和模拟能够进行,没有任何问题。那么,为什么我使用的多路复用器数量如此之少?任何帮助都将不胜感激。
为简洁起见,相关的库、端口映射和信号声明被排除在外。
process (clk)
variable fsm : integer range 0 to 3:= 0;
variable i : integer range 0 to 127:= 0;
begin
if rising_edge(clk) then
if fsm = 0 then
tasiyici <= STD_LOGIC_VECTOR(to_signed(sample_1(i)* sample_2(i) , 16));
--sample1 and sample 2 are arrays with constant values
fsm := fsm +1;
elsif fsm = 1 then
wea_select <= '0';
wea_ram<= "1";
ram_write <= '0';
dina <= STD_LOGIC_VECTOR(tasiyici(15 downto 8));
mult_out<= STD_LOGIC_VECTOR(tasiyici(15 downto 8));
fsm := fsm +1;
elsif fsm = 2 then
address_write <= std_logic_vector(unsigned(addra) + 1);
wea_ram<= "0";
i := i+1 ;
if i=128 then
fsm:=3;
ram_write <= '1';
wea_select <= '1';
else
fsm := 0;
end if;
end if;
end if;
end process;
----FFT process---
process(clk)
variable fsm : integer range 0 to 7:= 0;
variable i : integer range 0 to 128;
variable counter : integer range 0 to 2:= 0;
variable j : integer range 0 to 512;
begin
if rising_edge(clk) then
if fsm = 0 then -- ram_write is control
if ram_write = '1' then
wea_fft <= "0";
fsm:= 1;
end if;
elsif fsm = 1 then --process start (pulse)
start <= '1';
fwd_inv_we <= '1';
fsm := fsm +1;
elsif fsm = 2 then
start <= '0';
fwd_inv_we <= '0';
fsm := fsm +1;
elsif fsm =3 then --128 cycle send data from douta to xn_re
if i= 128 then
fsm := fsm +1;
else
xn_re <= douta;
address_read <= std_logic_vector(unsigned(addra) + 1);
i:=i+1;
fsm := 3;
end if;
elsif fsm =4 then --all data sent. process complete
if done = '1' then --wait for done finish 3 clk cycle, then unload
if counter= 2 then
fsm := fsm +1;
else
counter := counter +1;
fsm :=4;
end if;
end if;
elsif fsm =5 then
counter := 0;
unload <= '1';
fsm := fsm +1;
fft_data_ready <= "1";
wea_fft<= "1";
elsif fsm =6 then --wait 512 clk cycle to read all outputs
unload <= '0';
wea_fft<= "0";
if dv = '1' then
fft_output <= std_logic_vector(signed(xk_re(15 downto 4))*signed(xk_re(15 downto 4))
+signed(xk_im(15 downto 4))*signed(xk_im(15 downto 4)));
if j=512 then
fsm:=fsm+1;
else
j:=j+1;
fsm:=6;
end if;
else
fsm:=6;
end if;
end if;
end if;
end process;发布于 2014-10-23 18:20:53
看起来你的设计已经被简单地优化了。
您应该检查合成的RTL,以检查您的设计是否按您想要的方式进行了合成
https://stackoverflow.com/questions/26454147
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