I PRP B-PRPa DT B-DTsoul NN B-NN
am VBP B-VBPsadJJ B-JJ每条记录都用空行分隔。如果有一个输入,我是一个快乐的灵魂,我想搜索在这个文件和删除记录,如果它是存在的。在本例中,记录1将从文件中删除。因为句子是多行的,所以我想不出怎么做。我试过sed,awk,grep。sed -e '/I/,/soul
例如,其中一行如下所示:Soul CaliburSoulcalibur IISoul Calibur II现在假设我想查找包含"Soul Calibur“的行,我使用:
SELECT * FROM games WHERE spellings LIKE '%Soul Calibur%'这样做的问题是它返回两行,因为从技术上讲,第二行确实有"Sou
s = "that’s awful, Find – Best Quotes, “Music gives a soul to the universe, wings to the mind, flight我想把这个字符串转换成"that’s awful, Find - Best Quotes, "Music gives a soul to the universe, wings to the mind,“这太可怕了,找到了最好的格言,音乐给了宇宙一个灵魂,给了心灵翅膀,给了想象力,给了一切生命。柏拉图。”
我有以下格式的数据:[1960, Mary's story, "She liked her souland tried to sold it, but Alice had no soul and killed him.in 1987','She liked her soul, but decided to sold it anyway.','Pet
我尝试在不删除匹配字符串的情况下拆分字符串,我取得了一定的成功,因为我发现可以使用(?<=-)|(?=-),但现在如果我实现它来提取链接,使用下面的regex表达式: ((?实际上,拆分以下输入: A wonderful serenity has taken possession of http://www.google.com my entire soul,\n like", "c", "o", "m", "my entire soul</em