我想知道由"contactID“或"PhoneNumber”打开contactID,然后启动活动
本教程看上去不错:
Uri uri = Uri.withAppendedPath(ContactsContract.Contacts.CONTENT_URI, String.valueOf(mPerson.getContactID()));
/Symfony/src/Dim/WebsiteBundle/Service/QuickContact.php第47行中类"Dim\WebsiteBundle\Service\QuickContact“namespace(命名空间Dim\WebsiteBundle\ service ):{
private $formFactory$this->request->getSess
function.include]: failed to open stream: No such file or directory in /home/aap/public_html/justevents.net.au/quickcontact.phpfunction.include]: failed to open stream: No such file or directory in /home/aap/public_html/justevents.net.au/<em