SELECT jargons.jargon as jargon, jargons.example= 0, (SELECT jargon FROM jargons WHERE id = jargons.rootJargon), NULL) as rootJargonNameORDER BY jargons.id D
我有以下过程的XML
<p>In technical jargon<sup></sup>, the expect<span class="insert"></span><span class="insert<p>In technical jargon, the expect<span class="insert">ed</span> excess return on a fact
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