for (i in 1:5) { if ( (hispn[j,"FAMINC17"]>qq_hispn[i])&&(hispn[j,<=qq_hispn[5] & Stimulants==1 ~ 4
FAMINC17>qq_hispn[4] & FAMINC17<=qq_hispn[5] & Stimul
结果是N4JOJ7yZTi5urACYrKW5QQ,应该是N4JOJ7yZTi5urACYrKW5QQ==search =,以便after -> ( there is noend OR<code>E 218</code> there is no [=])
'a=N4JOJ7yZTi5urACYrKW5QQ=='.split(/\=(?!(