我明白了,这是因为系统认为我试图更新ORACLE_USER表。不管怎么说,这附近有吗?UPDATESELECTFROMJOIN IFSAPP.ORACLE_ACCOUNT oaoa.USERNAMEJOIN IFSAPP.table2 up ut.oracle_user = up.user_name up.default_value <> '11'
AND oa
16 17 187 8 9 10 11 12第一行中的计算-一次只考虑两个矩阵中的四个元素(0表示填充):
(1-8)+(2-9)+(3-10)+(4-(2-9)+(3-10)+(4-11)+(5-12): This replaces 2 in initial matrix.(3-10)+(4-11)+(5-12)+(6-0): This replaces 3 in initial matrix.(4-11)+(5-12)+(6-0)+(0-0): This replac
[OA_ID] FROM [Operating_Authority_Table] WHERE [OA_Name] = [@OA_Name]";
但是,当我将“@OA_Name”更改为在表中找到的简单值时command.CommandText = "SELECT [OA_ID] FROM [Operating_Authority_Table] WHERE [OA_Name] = ['OA 101']";] FROM [Op