mysql_query("SELECT * FROM admin_nav1 WHERE Active = 'YES' AND WHERE LinkedID = '$WID' ORDER by 'OrderSet' ASC") or die(mysql_error());
您的SQL语法出现了错误;请检查与您的MySQL服务器版本对应的手册,以获得在第1行“OrderSet‘ASC”中使用“WHERE LinkedID =
我遇到了一个奇怪的问题,mysql不喜欢我的表名。mysql> DROP TABLE IF EXISTS 6e0OU1QgkU7Pj6ycQF0U_results;
ERROR 1064 (42000): You have an error in yourSQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to usenear '6e