, DataPaid, AmountPaid, EmployeeID
AddressID, Address, City, EmployeeID1.统计住在伦敦金融城的雇员人数我的尝试:WHERE City='London'; SELECT SUM(AmountPaid) AS TotalPaid FROM Salary
WHERE Ci
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Chrome我确信问题出在我的一些员工ids以数字开头。我拥有的任何以alpha开头的员工id都没有问题。我确信有一个简单的解决方案,但我在谷歌上搜索正确的东西时遇到了麻烦。长var名称是动态员工编号。