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- 来自专栏Pythonista
day25 map,filter,reduce 内置函数,作业
[d]>20,shares)) print(res) ################################################## =====================作业三 #如下，每个小字典的name对应股票名字，shares对应多少股，price对应股票的价格 portfolio = [ {'name': 'IBM', 'shares': 100, 'price ': 91.1}, {'name': 'AAPL', 'shares': 50, 'price': 543.22}, {'name': 'FB', 'shares': 200, 'price ': 21.09}, {'name': 'HPQ', 'shares': 35, 'price': 31.75}, {'name': 'YHOO', 'shares': 45, 'price ': 16.35}, {'name': 'ACME', 'shares': 75, 'price': 115.65} ] 1:map来得出一个包含数字的迭代器，数字指的是：购买每支股票的总价格
52110发布于 2018-08-31 - 来自专栏简说基因
Python在生物信息学中的应用：同时对数据做转换和换算
for x in s)) # Data reduction across fields of a data structure portfolio = [ {'name':'GOOG', 'shares ': 50}, {'name':'YHOO', 'shares': 75}, {'name':'AOL', 'shares': 20}, {'name':'SCOX', 'shares ': 65} ] min_shares = min(s['shares'] for s in portfolio) 讨论 上述解决方案展示了当把生成器表达式作为函数的单独参数时在语法上的一些微妙之处，即不必重复使用括号 例如在 portfolio 的例子中，可以使用下面的替代方案： # Original: Returns 20 min_shares = min(s['shares'] for s in portfolio ) # Alternative: Returns {'name': 'AOL', 'shares': 20} min_shares = min(portfolio, key=lambda s: s['shares
23710编辑于 2024-02-21 - 来自专栏Linux云计算网络
从一个集合中查找最大最小的N个元素——Python heapq 堆数据结构
1 >>> portfolio = [ 2 {'name': 'IBM', 'shares': 100, 'price': 91.1}, 3 {'name': 'AAPL', 'shares ': 50, 'price': 543.22}, 4 {'name': 'FB', 'shares': 200, 'price': 21.09}, 5 {'name': 'HPQ', 'shares': 35, 'price': 31.75}, 6 {'name': 'YHOO', 'shares': 45, 'price': 16.35}, 7 {'name' ': 45}, {'price': 21.09, 'name': 'FB', 'shares': 200}, {'price': 31.75, 'name': 'HPQ', 'shares': 35}] ': 50}, {'price': 115.65, 'name': 'ACME', 'shares': 75}, {'price': 91.1, 'name': 'IBM', 'shares': 100
2.1K100发布于 2018-01-11 python练习题-day16
{'name': 'AAPL', 'shares': 50, 'price': 543.22}, {'name': 'FB', 'shares': 200, 'price': 21.09}, {'name': 'HPQ', 'shares': 35, 'price': 31.75}, {'name': 'YHOO', 'shares': 45, 'price': 16.35}, {' portfolio = [ {'name': 'IBM', 'shares': 100, 'price': 91.1}, {'name': 'AAPL', 'shares': 50, 'price': 543.22}, {'name': 'FB', 'shares': 200, 'price': 21.09}, {'name': 'HPQ', 'shares': 35, 'price': 31.75} , {'name': 'YHOO', 'shares': 45, 'price': 16.35}, {'name': 'ACME', 'shares': 75, 'price': 115.65}] 6.
51220发布于 2019-10-23- 来自专栏葫芦
python heapq
,{'name':'TEN','shares':231,'price':20} ... ,{'name':'FUN','shares':12,'price':58}] >>> cheap = heapq.nsmallest(3,portfolio,key=lambda s:s['price ']) >>> cheap [{'price': 20, 'name': 'TEN', 'shares': 231}, {'price': 32.1, 'name': 'IBM', 'shares': 100}, {'price': 58, 'name': 'FUN', 'shares': 12}] >>> expensive=heapq.nlargest(3,portfolio,key=lambda ', 'shares': 100}, {'price': 20, 'name': 'TEN', 'shares': 231}] >>>
41320发布于 2019-04-17 基于go使用redis实现简易排行榜功能
= append(shares, share)}}// 填充空的排行榜排名至十个emptyShare := Share{Id: "虚位以待",ViewCount: 0,}for len( shares) < 10 {shares = append(shares, emptyShare)}// 由于获取排行榜时有可能排行榜的Zset发生变动，需要按照确定的播放数重新排名一次sort.Slice (shares, func(i, j int) bool {return shares[i].ViewCount > shares[j].ViewCount})ctx.JSON(200, shares) shares) < 10 {shares = append(shares, emptyShare)}// 由于获取排行榜时有可能排行榜的Zset发生变动，需要按照确定的播放数重新排名一次sort.Slice (shares, func(i, j int) bool {return shares[i].ViewCount > shares[j].ViewCount})ctx.JSON(200, shares)
52410编辑于 2024-05-22- 来自专栏TechFlow
EasyC++58，构造函数
比如我们还是之前的类： class Stock { private: std::string company; long shares; double share_val ; double total_val; void set_tot() {total_val = shares * share_val;} public: void can't be negative;" << company << " shares set to 0. \n"; shares = 0; }else { shares = n; share_val = pr; set_tot(); ) {} 如果一致的话，就会出现这样的代码： shares = shares; 为了避免这种混乱，一般会在代码风格层面加以区分。
23710编辑于 2022-08-26 - 来自专栏sktj
python 类装饰器与元类
, key, value(key)) return cls return decorate Example @check_attributes(name=SizedString(size=8), shares =UnsignedInteger, price=UnsignedFloat) class Stock: def init(self, name, shares, price): self.name = name self.shares = shares self.price = price 另外一种方式是使用元类： A metaclass that applies checking class = UnsignedInteger() price = UnsignedFloat() def __init__(self, name, shares, price): self.name = name self.shares = shares self.price = price
1K20发布于 2019-12-13 - 来自专栏AI SPPECH
037_密码学实战：安全多方计算MPC技术深度解析——从秘密共享到隐私保护计算的完整指南
= 5 # 生成的总份额数 # 生成份额 shares = generate_shamir_shares(secret, threshold, num_shares) # 生成份额 shares = generate_additive_shares(secret, num_shares) print(f"生成的份额: {shares}") 将三元组分成份额 a_shares = generate_additive_shares(a, num_parties, prime) b_shares = generate_additive_shares y_shares, b_shares)] # 4. z_i = (c_shares[i] + d_b_shares[i] + e_a_shares[i] + de_shares[i]) % prime z_shares.append(z_i
64410编辑于 2025-11-18 - 来自专栏院长运维开发
samba服务安装脚本
Guest Users,Username for Guest: "tom" #Shared Directories 共享文件 #Share Name: "Share 1" #File Path: "/shares yes map to guest = bad user guest account = tom cups options = raw [Share 1] path = /shares comment = All Printers guest ok = yes EOF # Make sure shared directories exist... mkdir -p /shares if `selinuxenabled` then semanage fcontext -a -t samba_share_t '/shares(/.*)?' restorecon -FRvv /shares fi # Enable and start samba service... systemctl enable smb systemctl start
1.1K20发布于 2020-09-07 - 来自专栏Pythonista
day24,python习题
i) ----------------------------------------------------------------------------------------------- shares , 'lenovo':27.3, 'huawei':40.3, 'oldboy':3.2, 'ocean':20.1 } 问题一：得出股票价格大于30的股票名字列表 for i in shares : if shares[i] > 30: print (i) ---------------------------------------------------------- -- i=[i for i in shares if shares[i] > 30] print(i) ------------------------------------------------- --------------------- 问题二：求出所有股票的总价格 print((i for i in shares.values())) --------------------------
52820发布于 2018-08-31 - 来自专栏sktj
python nlargest nsmallest
, 37, 23] print(heapq.nsmallest(3, nums)) # Prints [-4, 1, 2] dict portfolio = [ {'name': 'IBM', 'shares ': 100, 'price': 91.1}, {'name': 'AAPL', 'shares': 50, 'price': 543.22}, {'name': 'FB', 'shares': 200 , 'price': 21.09}, {'name': 'HPQ', 'shares': 35, 'price': 31.75}, {'name': 'YHOO', 'shares': 45, 'price ': 16.35}, {'name': 'ACME', 'shares': 75, 'price': 115.65} ] cheap = heapq.nsmallest(3, portfolio,
55230发布于 2019-09-25 - 来自专栏云原生运维社区
JVM 如何获取当前容器的资源限制？
is /sys/fs/cgroup/cpu,cpuacct/cpu.shares CPU Shares is: 681 CPU Quota count based on quota/period: 4 CPU Share count based on shares: 1 OSContainer::active_processor_count: 4 Path to /cpu.cfs_quota_us is /sys/fs/cgroup/cpu,cpuacct/cpu.shares CPU Shares is: 681 CPU Quota count based on quota/period: 4 CPU Share count based on shares: 1 OSContainer::active_processor_count: 4 …… java version "1.8.0_191 也可以通过 cpu.shares 来获取： $ cat /sys/fs/cgroup/cpu,cpuacct/cpu.shares 681 不过这个值是 CPU 占用份额，无法根据这个算出来可用 CPU
1.2K10编辑于 2024-04-11 - 来自专栏FreeBuf
PowerHuntShares：一款针对活动目录域安全的分析与审计工具
o Identify shares that provide reads & write access o Identify shares thare are high risk from 49 computers [*][03/01/2021 09:36] - 217 SMB shares were found. [*][03/01/2021 09:36] Getting share permissions from 217 SMB shares [*][03/01/2021 09:37] - 374 share permissions were enumerated ] [*][03/01/2021 09:37] SHARE SUMMARY [*][03/01/2021 09:37] - 217 shares were found. are typically two default shares. [*][03/01/2021 09:37] - 46 (21.20%) shares across 32 systems were
1.6K30编辑于 2023-02-10 - 来自专栏Kubernetes
docker-monitor-injector源码分析
user_sum: cpuacct.stat.user system_sum: cpuacct.stat.system nice_sum: (_self*cpu.shares/1024)/sysconf (_SC_NPROCESSORS_ONLN) idle_sum: (_self*cpu.shares/1024)/sysconf(_SC_NPROCESSORS_ONLN) iowait_sum: (_self*cpu.shares/1024)/sysconf(_SC_NPROCESSORS_ONLN) irq_sum: (_self*cpu.shares/1024)/sysconf(_SC_NPROCESSORS_ONLN ) softirq_sum:(_self*cpu.shares/1024)/sysconf(_SC_NPROCESSORS_ONLN) steal_sum: (_self*cpu.shares/1024 )/sysconf(_SC_NPROCESSORS_ONLN) guest_sum: (_self*cpu.shares/1024)/sysconf(_SC_NPROCESSORS_ONLN) 任一
1.1K90发布于 2018-04-13 - 来自专栏Reck Zhang
Ethereum 01 - 保证智能合约的安全可靠
> uint) shares; // withdraw your share function withdraw() { if(this.balance < shares { shares[msg.sender] = 0; } } } 在这段智能合约中, 有一个mapping类型的变量shares, 和一个withdraw 函数. shares记录着每个用户在Fund中拥有的”股权”, 假定一份Fund的股权等价于一个以太币. [msg.sender] = 0这句话, 而重复地执行msg.sender.call.value(shares[msg.sender])(). => uint) shares; // withdraw your share function withdraw() { uint share = shares[msg.sender
45710发布于 2021-08-11 - 来自专栏GopherCoder
Python 强化训练： 第一篇
': 100, 'price': 91.1}, {'name': 'AAPL', 'shares': 50, 'price': 543.22}, {'name': 'FB', 'shares': 200 , 'price': 21.09}, {'name': 'HPQ', 'shares': 35, 'price': 31.75}, {'name': 'YHOO', 'shares': 45, 'price a["shares"]) print(cheap, "\n", expensive) # [{'price': 16.35, 'name': 'YHOO', 'shares': 45}, {'price ': 31.75, 'name': 'HPQ', 'shares': 35}] # [{'price': 543.22, 'name': 'AAPL', 'shares': 50}, {'price' : 21.09, 'name': 'FB', 'shares': 200}] 3.
75940发布于 2018-06-06 - 来自专栏Eric杂货铺
samba服务安装脚本
Guest Users,Username for Guest: "tom" #Shared Directories 共享文件 #Share Name: "Share 1" #File Path: "/shares passwords = yes map to guest = bad user guest account = tom cups options = raw [Share 1] path = /shares samba comment = All Printers guest ok = yes EOF # Make sure shared directories exist... mkdir -p /shares if `selinuxenabled` then semanage fcontext -a -t samba_share_t '/shares(/.*)?' restorecon -FRvv /shares fi # Enable and start samba service... systemctl enable smb systemctl start
91010发布于 2020-09-24 - 来自专栏数据科学实战
AkShare-股票数据-限售解禁
更新接口 "stock_restricted_shares" # 限售解禁 限售解禁 接口: stock_restricted_shares 目标地址: https://vip.stock.finance.sina.com.cn float Y - 解禁股流通市值(亿元) float Y - 上市批次 float Y - 公告日期 str Y - 接口示例 import akshare as ak stock_restricted_shares_df = ak.stock_restricted_shares(stock="600000") print(stock_restricted_shares_df) 数据示例 代码 名称
67900发布于 2020-05-22 - 来自专栏码神随笔
当我学会了类，就离领悟面向对象编程不远了（基础）！！（熬夜爆肝）
; double share_val; double total_val; void set_tot() { total_val = shares * share_val; } public can't be negative"//股数非负 << comany << "shares set to 0. \n"; shares = 0; } else shares = n; share_val = pr; set_tot(); } void Stock::buy(long num, double price) { if (num < 0) { cout << "Number of shares sold can't be negative." : " << shares << '\n' << "Share price: " << share_val << "Total Worth: " << total_val << '\n'; }
26920编辑于 2022-12-13
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