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车牌检测识别--Towards End-to-End Car License Plates Detection and Recognition with Deep Neural Networks
Towards End-to-End Car License Plates Detection and Recognition with Deep Neural Networks https://arxiv.org
1.6K90发布于 2018-01-03 - 来自专栏python3
用turtle库显示汉诺塔问题的过程
(n):#制造n个盘子 35 plates=[turtle.Turtle() for i in range(n)] 36 for i in range(n): 37 plates [i].up() 38 plates[i].hideturtle() 39 plates[i].shape("square") 40 plates[i]. shapesize(1,8-i) 41 plates[i].goto(-400,-90+20*i) 42 plates[i].showturtle() 43 return 48 49 def moveDisk(plates,poles,fp,tp):#把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp] 50 mov (plates,poles,height-1,fromPole,withPole,toPole) 59 moveDisk(plates,poles,fromPole,toPole) 60
64040发布于 2020-01-16 - 来自专栏福大大架构师每日一题
2022-03-30：有m个同样的苹果，认为苹果之间无差别， 有n个同样的盘子，认为盘子之间也无差别， 还有，比如5个苹果如果放进3个盘子， 那么1、3、1和1
i <= 10; i++ { for j := 0; j <= 10; j++ { dp[i][j] = -1 } } } return process3(apples, plates , dp) } func process3(apples, plates int, dp [][]int) int { if dp[apples][plates] ! = -1 { return dp[apples][plates] } ans := 0 if apples == 0 { ans = 1 } else if plates == 0 { ans = 0 } else if plates > apples { ans = process3(apples, apples, dp) } else { ans = process3 (apples, plates-1, dp) + process3(apples-plates, plates, dp) } dp[apples][plates] = ans return ans
33310编辑于 2022-03-30 - 来自专栏包子铺里聊IT
Google Code Jam 2020 Qualification Round: Vestigium Solution
Patel has N stacks of plates. Each stack contains K plates. Patel needs to pick P = 5 plates: He can pick the top 3 plates from the first stack (10 + 10 + 100 = Patel needs to pick P = 3 plates: He can pick the top 2 plates from the first stack (80 + 80 = 160). j] plates from the i-th stack and [j, j-1, ..., 0] plates from the previous i-1 stacks respectively. plates = new Plates(); 7 8 while (caseNum <= testCases) { 9 int n = s.nextInt(); 10
88110发布于 2020-05-21 - 来自专栏AngelNI
python实现汉诺塔移动可视化
(n):#制造n个盘子 plates=[turtle.Turtle() for i in range(n)] for i in range(n): plates[i].up () plates[i].hideturtle() plates[i].shape("square") plates[i].color("blue") plates[i].shapesize(1,8-i) plates[i].goto(-400,-90+20*i) plates[i].showturtle() return (plates,poles,fp,tp):#把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp] mov=poles[fp].peek() plates :\n")) plates=creat_plates(n) poles=pole_stack() for i in range(n): poles[0].push(i) moveTower(plates
1.2K21发布于 2020-04-16 - 来自专栏福大大架构师每日一题
2022-03-30：有m个同样的苹果，认为苹果之间无差别，有n个同样的盘子，认为盘子之间也无差别
"fmt" func main() { ret := ways3(5, 4) fmt.Println(ret) } var dp [][]int func ways3(apples, plates for j := 0; j <= 10; j++ { dp[i][j] = -1 } } } return process3(apples, plates , dp) } func process3(apples, plates int, dp [][]int) int { if dp[apples][plates] ! = -1 { return dp[apples][plates] } ans := 0 if apples == 0 { ans = 1 } else if plates ans = process3(apples, plates-1, dp) + process3(apples-plates, plates, dp) } dp[apples][plates] =
19850编辑于 2022-04-13 - 来自专栏python3
python 游戏 —— 汉诺塔(Han
(n):#制造n个盘子 35 plates=[Turtle() for i in range(n)] 36 for i in range(n): 37 plates[i] .up() 38 plates[i].hideturtle() 39 plates[i].shape("square") 40 plates[i].shapesize (1,8-i) 41 plates[i].goto(-400,-90+20*i) 42 plates[i].showturtle() 43 return plates ,poles,fp,tp):#把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp] 50 mov=poles[fp].peek() 51 plates （恰好放在原来最上面的盘子上面） 54 plates[mov].goto((tp-1)*400,-90+20*l) 55 56 def moveTower(plates,poles,height
1.8K10发布于 2020-01-17 - 来自专栏CSDN旧文
CodeForces - 140A New Year Table （几何题）当时没想出来-----补题
Gerald invited many guests and is concerned whether the table has enough space for plates for all those Consider all plates to be round and have the same radii that equal r. Of course, the plates must not intersect, but they can touch each other. Help Gerald determine whether the table is large enough for n plates. , the radius of the table and the plates’ radius.
71630发布于 2020-10-28 - 来自专栏AI那点小事
放苹果
代码如下: import java.util.Scanner; public class Main { public static int Function(int apples,int plates ){ if (plates > apples){ //盘子数大于苹果数的情况，抛弃plates-apples个盘子 return Function -1)+Function(apples-plates,plates); } public static void main(String[] args) { // TODO (); for( int i = 0 ; i < cnt ; i++){ int apples = in.nextInt(); int plates = in.nextInt(); System.out.print(Function(apples, plates)); } in.close()
87010发布于 2020-04-20 - 来自专栏iRF射频前端产业观察
HEMTs:Air-bridge to improve field-plate performance
Researchers in China and Canada have developed air-bridge field plates for nitride semiconductor high-electron-mobility Field plates are used to manipulate electric field distributions in HEMTs. The air-bridge field plates were proposed as an attempt to reduce some of these effects. The researchers produced HEMTs with conventional field plates (CFP, Figure 1a) and air-bridge field plates Using an air-bridge greatly reduced the gate–source capacitance compared with conventional field plates
65220编辑于 2022-05-16 - 来自专栏zaking's
用js来实现那些数据结构05（栈02-栈的应用）
我们已经对汉诺塔有了简单的了解，那么我们看看如何用栈来实现这个游戏吧： //plates:盘子数量，source源柱子，helper暂存柱子，dest目标柱子，sourceName源柱子名称，helperName if (plates <= 0) return moves; if (plates === 1) { dest.push(source.pop()); const move = { return towerOfHanoi(plates, source, helper, dest, 'source', 'helper', 'dest'); } //这个方法是计算在汉诺塔的层数为plates 的时候，每一个是从哪个柱子拿到哪个柱子的 function hanoi(plates, source, helper, dest, moves = []) { if (plates <= 0) return moves; if (plates === 1) { moves.push([source, dest]); } else { hanoi(plates - 1, source
99870发布于 2018-05-02 - 来自专栏Edward的专栏
基于 opencv+yolov8+easyocr的车牌追踪识别
print(detection) detections_ = [] 如果检测到车辆，则放入列表中 检测车牌，并将车牌分配给对应的车辆： # 检测车牌 licence_plates = license_plate_detector(frame)[0] for licence_plate in licence_plates.boxes.data.tolist(): ']['bbox'] bbox_score = results[frame_nmr][car_id]['licence_plates']['bbox_score' text_score = results[frame_nmr][car_id]['licence_plates']['text_score'] # 写入数据行 = license_plate_detector(frame)[0] for licence_plate in licence_plates.boxes.data.tolist():
62610编辑于 2025-07-13 - 来自专栏全栈程序员必看
用js来实现那些数据结构05（栈02-栈的应用）「建议收藏」
我们已经对汉诺塔有了简单的了解，那么我们看看如何用栈来实现这个游戏吧： //plates:盘子数量，source源柱子，helper暂存柱子，dest目标柱子，sourceName源柱子名称，helperName if (plates <= 0) return moves; if (plates === 1) { dest.push(source.pop()); const move = { return towerOfHanoi(plates, source, helper, dest, 'source', 'helper', 'dest'); } //这个方法是计算在汉诺塔的层数为plates 的时候，每一个是从哪个柱子拿到哪个柱子的 function hanoi(plates, source, helper, dest, moves = []) { if (plates <= 0) return moves; if (plates === 1) { moves.push([source, dest]); } else { hanoi(plates - 1, source
47320编辑于 2022-07-20 - 来自专栏ACM算法日常
UVA10129：Play on Words（欧拉回路）
There is a large number of magnetic plates on every door. Every plate has one word written on it. The plates must be arranged into a sequence in such a way that every word begins with the same letter program that will read the list of words and determine whether it is possible to arrange all of the plates Output Your program has to determine whether it is possible to arrange all the plates in a sequence such All the plates from the list must be used, each exactly once.
59610发布于 2018-08-07 - 来自专栏趣谈前端
安利一款好用到爆的可视化拖拽库
return false; } const draggable = new Draggable(container, { draggable: '.Plate', }); const plates new Plate(container); // --- Draggable events --- // draggable.on('drag:start', (evt) => { plates.setThreshold (); plates.setInitialMousePosition(evt.sensorEvent); }); draggable.on('drag:move', (evt) => // requestAnimationFrame(() => {}); plates.dragWarp(evt.source, evt.sensorEvent); }); draggable.on ('drag:stop', () => { plates.resetWarp(); }); return draggable; } 2.
98010编辑于 2024-04-14 - 来自专栏程序那些事儿
PHP八大模板引擎
{{/in_ca}} Plates plates是一个原生PHP模板系统，快速，易于使用，易于扩展是它的特性。它受到出色的 Twig 模板引擎的启发，并努力将现代模板语言功能引入 PHP 模板中。 plates原生的PHP 模板而不是编译的模板语言（如 Twig 或 Smarty），因此受到对速度要求极致的开发人员喜爱。 此模板引擎具有： 原生的 PHP 模板，无需学习新语法 plates是模板系统，而不是模板语言 plates鼓励使用现有的PHP函数 通过模板布局和继承增加代码重用 用于将模板分组到命名空间的模板文件夹
3.2K30编辑于 2023-07-24 - 来自专栏小明的数据分析笔记本
跟着Nat. Biotechnol.学作图:R语言ComplexHeatmap热图展示TCGA-BRCA数据集概况
plate_RNAseq)) # 38 colfunc <- grDevices::colorRampPalette( RColorBrewer::brewer.pal(11, 'PRGn')[-6]) color.plates cluster_rows = FALSE, cluster_columns = FALSE, column_names_gp = grid::gpar(fontsize = 12), col = color.plates , name = 'Plates', heatmap_legend_param = list( color_bar = "discrete" , ncol = 4, title_gp
62210编辑于 2023-01-06 - 来自专栏相约机器人
实用的AI：使用OpenAI GPT2，Sentence BERT和Berkley选区解析器从任何内容自动生成对或错问题
As tectonic plates pull away from each other at a divergent plate boundary, they create deep fissures As tectonic plates pull away from each other at a divergent plate boundary, they create deep fissures As tectonic plates pull away from each other at a divergent plate boundary, they create deep fissures 最终作品： 1) True Sentence (from the story) : As tectonic plates pull away from each other at a divergent they create deep fissures, or cracks, in the crust False Sentences (GPT-2 Generated) a) As tectonic plates
1.2K20发布于 2020-04-02 - 来自专栏mythsman的个人博客
一款开源的车牌号码识别系统OpenALPR
Maryland, ca for California) --clock Measure/print the total time to process image and all plates <image_file_path> Image containing license plates OpenAlpr Command Line Utility 效果： myths@myths-X450LD
2.8K30编辑于 2022-11-14 - 来自专栏yl 成长笔记
opencv 视觉项目学习笔记（二）： 基于 svm 和 knn 车牌识别
== 0); _findclose(hFile); // 关闭句柄 } } void Preprocess::extract_img_data(string path_plates numPlates; i++) { stringstream ss(stringstream::in | stringstream::out); ss << path_plates SVM::load("model.xml"); // For each possible plate, classify with svm if it's plate vector<Plate> plates p.convertTo(p, CV_32FC1); int reponse = (int)model->predict(p); if (reponse) { plates.push_back
3.5K20发布于 2018-10-11
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