本文作者:小驹[1] Carrot 是一个ERC20 代币[2],漏洞存在于代币的合约中。合约中存在两个漏洞代码注入和逻辑错误,通过漏洞利用,可以达到转移任意用户的 Carrot 代币。 一句话总结漏洞利用过程:利用代码注入漏洞 Carrot 合约通过调用 pool 合约的方法成为 pool 合约的 owner,利用逻辑漏洞绕过转账时的授权检查。 代币授权给 0x9b7325a150254df59d7253885d41d8d3310f9c1a PancakeRouter 将 Carrot 代币授权给 hackCon 调用 Carrot.transReward 合约转了 0 个 Carrot 代币。 carrot = Carrot(CARADDR); carrot.approve(PANCAKEROUTER, ~uint(0)); carrot.transReward
基于Java的开源 Carrot2 搜索结果聚合聚类引擎 2.0发布了 专注是不断前进的指南针 --- 题记 基于Java的开源 Carrot2 搜索结果聚合聚类引擎 2.0发布了. Carrot2 可以自动的把自然的搜索结果归类(聚合聚类)到相应的语义类别中,这个功能是通过Carrot2一个现成的组件完成的,除此之外Carrot2 还包括了很多其他的搜索结果聚合聚类算法 search Carrot2 2.0 的一个亮点是速度和易用性的提高。 Carrot2 的流行还衍生了一家叫 Carrot Search 的公司,类似jboss ,mysql 相关的运营公司, 他们发布了发布了 Lingo3G ,可以想想出来了,Lingo3G ( 这个名字真酷 Let's Go 相关阅读: 原文地址 译文地址 新闻阅读器 Carrot2 live demo 这是他们的 项目地址.
@VM-0-16-centos ~]$ ll total 4 drwxrwxr-x 2 carrot carrot 4096 Dec 24 14:06 dir1 [carrot@VM-0-16-centos ~]$ ll dir1 total 8 -rw-rw-r-- 1 carrot carrot 6 Dec 24 14:06 hello.txt -rw-rw-r-- 1 carrot carrot total 4 d-wxrwxr-x 2 carrot carrot 4096 Dec 24 14:06 dir1 # 将拥有者的 r 权限删除之后,可以正常进入 [carrot@VM-0-16-centos [carrot@VM-0-16-centos ~]$ ll total 4 dr-xrwxr-x 2 carrot carrot 4096 Dec 24 14:06 dir1 [carrot@VM-0 ]$ ll total 8 -rw-rw-r-- 1 carrot carrot 6 Dec 24 14:06 hello.txt -rw-rw-r-- 1 carrot carrot 10 Dec
题目 来源:https://tianchi.aliyun.com/oj/210874425247820050/215397455965131519 给定一个n * m 的矩阵 carrot, carrot 示例 1: 输入: carrot = [[5, 7, 6, 3], [2, 4, 8, 12], [3, 5, 10, 7], [4, 16, 4, 17]] 输出: 83 解释:起点坐标是(1, 1), 移动路线是:4 -> 8 -> 12 -> 7 -> 17 -> 4 -> 16 -> 5 -> 10 示例 2: 输入: carrot = [[5, 3, 7, 1, 7], [4, 解题 class Solution { public: /** * @param carrot: an integer matrix * @return: Return the // write your code here int m = carrot.size(), n = carrot[0].size(); int x = (m-1)/2,
','012');INSERT INTO exprs VALUES(3,'rabbit','0ea');INSERT INTO exprs VALUES(3,'carrot','66734');INSERT ;carrot;clion;rabbit--使用group by进行分组SELECT id,LISTAGG(name,' ') within GROUP(ORDER BY name) FROM exprs 3 apple carrot rabbit 2 clion-- 多插入几行数据使能发生溢出情况DELETE exprs;INSERT INTO exprs(name carrot carrot 2 clion clion clion 3 apple rabbit ,carrot,apple apple 3 carrot rabbit,carrot,apple carrot 3 rabbit rabbit,carrot
New password: # sudo usermod -aG carrot carrot1 将carrot1添加到carrot的组中 [carrot@VM-0-16-centos ~]$ sudo usermod -aG carrot carrot1 # groups carrot 查看carrot在哪个组中 [carrot@VM-0-16-centos ~]$ groups carrot carrot -r--r-- 2 carrot carrot 4096 Dec 22 22:28 dir -r--rw-r-- 1 carrot carrot 9 Dec 23 10:45 hello.txt [carrot@VM-0-16-centos ~]$ chown carrot1 hello.txt 这种写法是错误的,更改文件的拥有者不仅和自己(carrot)有关,还和另一个人(carrot1)有关 # 将hello.txt文件的拥有者和所属组都更改为carrot1 [carrot@VM-0-16-centos ~]$ sudo chown carrot1:carrot1 hello.txt #
", "carrot.routing.key", msg, new CorrelationData(UUID.randomUUID(). ", "carrot.routing.key", carrot ); } /** * 发送延迟胡萝卜(10秒后才送达 颜色: {}, 重量: {}g", carrot.getColor(), carrot.getWeight()); // 模拟复杂的处理逻辑 processLuxuryCarrot(carrot); // 手动确认(告诉兔子:我吃完了,你可以送下一个了 ) { // 复杂的业务逻辑 log.info("分析胡萝卜营养成分..."); log.info("维生素含量: {}", carrot.getVitamins
首先看下包的安装: install.packages('LinkageMapView') 我们直接通过实例来给大家演示下这个包的使用: library(LinkageMapView) data(carrot ) head(carrot) ? ##简单的展示结果 lmv.linkage.plot(mapthis= carrot,outfile = 'g.pdf') ? " lmv.linkage.plot( carrot, outfile = outfile, ruler = TRUE, lgtitle = c("2170","70349", "10117 outfile =file.path(tempdir(), "carrot.pdf") lmv.linkage.plot( carrot, outfile = outfile, ruler
Apple', 'Banana', 'Kiwi', 'Grape', 'Orange', 'Strawberry']*multvegetables = ['Asparagus', 'Broccoli', 'Carrot 列表中蔬菜不包含在 vegetablesExclude 列表中动物是 “Dog”输出结果为: Fruit Vegetable Animal xValue yValue0 Apple Carrot 79.0651 Banana Lettuce Cat 80.375 78.7152 Banana Rutabaga Dog 80.387 78.1933 Apple Carrot ..295 Grape Spinach Dog 79.008 79.768296 Orange Broccoli Cat 82.987 79.650297 Apple Carrot Dog 80.937 78.695298 Apple Carrot Cat 80.415 78.753299 Grape Carrot Dog 79.856
help(list) 列表的帮助,列出所有列表的用法 type(name) 判断数据类型是列表,元组或字典 1.1、增 >>> shoplist = ['apple','mango','carrot del shoplist[0] #方法1 根据索引删除列表中元素 >>> shoplist ['pear', 'mango', 'carrot > shoplist.remove('rice') #方法2 根据内容删除元素 >>> shoplist ['pear', 'mango', 'carrot pear mango carrot banana rice >>> for i,j in enumerate(shoplist): ... (shoplist)) {0: 'pear', 1: 'mango', 2: 'carrot', 3: 'banana'} >>> {k:v for k,v in enumerate(shoplist)
bin/python # Filename: using_list.py # This is my shopping list shoplist = ['apple', 'mango', 'carrot These items are: apple mango carrot banana I also have to buy rice. shopping list is ['apple', 'banana', 'carrot', 'mango', 'rice'] The first item I will buy is apple Item 3 is banana Item -1 is banana Item -2 is carrot Item 1 to 3 is ['mango', 'carrot'] Item 2 to end is ['carrot', 'banana'] Item 1 to -1 is ['mango', 'carrot'] Item start to end is ['apple', '
# -*- coding: utf-8 -*- shoplist = ['apple', 'mango', 'carrot', 'banana'] print "we copy the shoplist ', 'banana'] Now the mylist is : ['apple', 'mango', 'carrot', 'banana'] delete the first item ', 'carrot', 'banana'] This time we use slice to cope the shoplist "with mylist = shoplist[:]" delete the first item of mylist Now the shoplist is : ['mango', 'carrot', 'banana'] Now the mylist is : ['carrot', 'banana'] 6.字符串的方法 字符串也是对象,同样具有方法。
These items are: apple mango carrot banana I also have to buy rice. Item 3 is banana Item -1 is banana Item -2 is carrot Character 0 is s Item 1 to 3 is ['mango', 'carrot '] Item 2 to end is ['carrot', 'banana'] Item 1 to -1 is ['mango', 'carrot'] Item start to end is ['apple >>> shoplist = ['apple', 'mango', 'carrot', 'banana'] >>> shoplist[::1] ['apple', 'mango', 'carrot', , 'carrot', 'banana'] mylist is ['carrot', 'banana'] 代码是如何工作的?
Python 中的 list 里面的元素的数据类型也可以不同 初始化 shoplist = ['apple', 'mango', 'carrot', 'banana'] # ['apple', 'mango ', 'carrot', 'banana'] len() 函数 print('I have', len(shoplist), 'items to purchase.') # 4 索引 用索引来访问 list ') print('My shopping list is now', shoplist) # My shopping list is now ['coco', 'apple', 'mango', 'carrot ['carrot', 'banana'] print('Item 1 to -1 is', shoplist[1:-1]) # Item 1 to -1 is ['mango', 'carrot'] '] shoplist[::1] # ['apple', 'mango', 'carrot', 'banana'] shoplist[::2] # ['apple', 'carrot'] 集合(Set)
1 2 clustering-carrot2 : 一个搜索结果类聚的代码框架,目前和Egothor等搜 索引擎结合的很好; 地址:http://sourceforge.net /projects/carrot2 相关类:org.apache.nutch.clustering.OnlineClusterer Online Search Results Clustering Plugin org.apache.nutch.clustering.carrot2 Carrot2 Clusterer creativecommons : 一个创作共用的工具集合。
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/bin/python #-*- coding=utf-8 -*- print '-----------简单的赋值-----------' shoplist = ['apple','mango','carrot 'shoplist 列表:',shoplist print 'mylist 列表:',mylist 输出结果为: -----------简单的赋值----------- shoplist 列表: ['carrot ', 'banana'] mylist 列表: ['carrot', 'banana'] 完整切片是真正的复制: shoplist 列表: ['carrot', 'banana'] mylist 列表:
('id', 87, 'name', 'carrot') | +-----------------------------------------+ | {"id": 87, "name": "carrot --------------------------------+ 1 row in set (0.00 sec) mysql>SELECT JSON_OBJECT('id', 87, '', 'carrot '); +-------------------------------------+ | JSON_OBJECT('id', 87, '', 'carrot') | +------------ -------------------------+ | {"": "carrot", "id": 87} | +--------------------------------- ----+ 1 row in set (0.00 sec) mysql >SELECT JSON_OBJECT('id', 87, 'carrot'); ERROR 1582 (42000)
const fruits = ['apple', 'orange', 'banana']; const vegetables = ['carrot']; const fruitsAndVegetables = [...fruits, ...vegetables]; // ['apple', 'orange', 'banana', 'carrot'] const fruitsAndVegetables = ['carrot', ...fruits]; // ['carrot', 'apple', 'orange', 'banana'] // 老方法 const fruitsAndVegetables = fruits.concat(vegetables); fruits.unshift('carrot'); 将参数作为数组进行传递 当传递参数时,展开运算符能够使我们的代码更具可读性。
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