我正在尝试使用Agricolae包中的HSD.test对我的数据进行图基测试。但是,我的结果总是单词NULL。
我的数据:
structure(list(Sample = c(1011L, 1012L, 1014L, 1024L, 1025L,
1026L), Collection = c(1L, 1L, 1L, 1L, 1L, 1L), Irrigation = structure(c(3L,
3L, 3L, 5L, 5L, 5L), .Label = c("Rate1", "Rate2", "Rate3", "Rate4",
"Rate5"), class = "factor"), Variety = structure(c(2L, 1L, 3L,
3L, 2L, 1L), .Label = c("Hodag", "Lamoka", "Snowden"), class = "factor"),
Suc = c(0.7333, 0.4717, 0.5883, 0.6783, 0.8283, 0.6833),
Gluc = c(0.03, 0.04, 0.043, 0.075, 0.057, 0.087), L = c(59.48,
57.59, 59.25, 66.45, 68.29, 65.65), a = c(4.36, 6.85, 3.43,
1.7, 0.78, 2.84), b = c(26.82, 27.6, 26.2, 26.14, 25.37,
27.19), NoDefect = c(100L, 100L, 100L, 92L, 100L, 100L),
Defect = c(0L, 0L, 0L, 8L, 0L, 0L)), row.names = c(NA, 6L
), class = "data.frame")结合收集和灌溉因素(我想对这10个总共处理2种收集类型和5种灌溉类型的一组进行Tukey's ):
Tukey_data <- data %>%
mutate(Tukey_ID = paste(Collection, Irrigation, sep="_"))Anova:
Tukey_data$Tukey_ID <- as.factor(Tukey_data$Tukey_ID)
TukeyAov <- aov(Suc ~ Tukey_data$Tukey_ID, data = Tukey_data)Tukey的:
HSD.test(TukeyAov, "Tukey_ID", group=FALSE)返回:NULL
你知道为什么我的回答是空的吗?非常感谢!
发布于 2021-05-11 02:05:37
我遇到了同样的问题,并发现处理变量需要与模型中的完全一样进行标记。它将其读取为字符串,而不是标签。在您的情况下,您将需要trt = "Tukey_data$Tukey_ID"。在另一个示例中,当我定义我的模型时,我使用了as.factor(Tukey_ID)并需要将处理定义为trt = "as.factor(Tukey_ID)"
https://stackoverflow.com/questions/56706698
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