我如何修剪最高的重量在丹索尔流动层？tfmot.sparsity.keras.prune_low_magnitude

Question

我想修剪一个tf层的最高重量值。我正在考虑使用tf.nn.top_k，但我不太确定我将如何做到这一点。

文档：大小代码：

pruning_params = {
    'pruning_schedule': PolynomialDecay(initial_sparsity=0.2,
        final_sparsity=0.8, begin_step=1000, end_step=2000),
    'block_size': (2, 3),
    'block_pooling_type': 'MAX'
}

model = keras.Sequential([
    layers.Dense(10, activation='relu', input_shape=(100,)),
    prune_low_magnitude(layers.Dense(2, activation='tanh'), **pruning_params)
])

Answer 1

假设w是您想要修剪的层的权重矩阵，而k是应该修剪的权重的百分比，那么这应该对您有好处：

# Convert k from percentage to integer representing the number of weights
k = tf.cast(tf.round(tf.size(w, out_type=tf.float32) * tf.constant(k)), dtype=tf.int32)
# Reshape flatten the weight matrix
w_reshaped = tf.reshape(w, [-1])
# Select the indices of the largest k weights
_, indices = tf.nn.top_k(w_reshaped, k, sorted=True, name=None)
# Set the elements matching the indices to 0
mask = tf.scatter_nd_update(tf.Variable(tf.ones_like(w_reshaped, dtype=tf.float32), name="mask", trainable=False), tf.reshape(indices, [-1, 1]), tf.zeros([k], tf.float32))
# Update the weight matrix w
w.assign(tf.reshape(w_reshaped * mask, tf.shape(w)))

这是基于这个Github回购。请注意，在那个项目中，我正在修剪最小的k权重。