我正在使用由Sklearn进行的参数优化来制作一个Pipeline。管道必须为几个实现预训练和微调方法的不同实体获得最佳模型:预训练所有实体在一起,微调每一个元素,并为每个实体返回一个模型。这些都是管道的制约因素:
我已执行:
我所缺少的是如何将列车前变压器传递给微调变压器,即列车前变压器获得的权重(考虑到每个GridSearchCV折叠有不同的权重)。
以下是代码:
import pandas as pd
import numpy as np
import random
from sklearn.pipeline import Pipeline
from sklearn.model_selection import GridSearchCV
from sklearn.base import BaseEstimator, RegressorMixin, TransformerMixin
from sklearn.metrics import mean_squared_error
from keras.models import Model
from keras.layers import Dense, Input
import copy
class MyRegressor(BaseEstimator, TransformerMixin):
def __init__(self, neurons, featInput, featOutput):
self.neurons = neurons
self.preTrain = None
self.featInput = featInput
self.featOutput = featOutput
def fit(self, X, y=None):
X_train = X[self.featInput]
y_train = X[self.featOutput]
inputLayer = Input(shape=(len(self.featInput), ), name='INPUT')
hidden = Dense(self.neurons, name='HIDDEN')(inputLayer)
outputLayer = Dense(len(self.featOutput), name='OUTPUT')(hidden)
self.model = Model(inputLayer, outputLayer)
self.model.compile(loss='mse', optimizer='rmsprop')
if self.preTrain is not None:
self.model.loadWeights(self.preTrain)
self.model.fit(X_train, y_train)
return self
def predict(self, X):
return self.model.predict(X[self.featInput])
def transform(self, X):
return X
def score(self, X, y=None, sample_weight=None):
y_true = X[self.featOutput]
y_pred = self.predict(X)
return mean_squared_error(y_true, y_pred)
class LoopTransformer(BaseEstimator, TransformerMixin):
def __init__(self, columns, component):
self.columns = columns
self.component = component
self.components = []
def fit(self, X, y=None):
for index, idx in X[self.columns].drop_duplicates().iterrows():
entityDf = X[(X[self.columns] == idx).sum(axis=1) == len(self.columns)].copy()
self.components.append({'id': idx, 'component': copy.deepcopy(self.component)})
self.components[-1]['component'].fit(entityDf, y)
return self
def predict(self, X):
results = []
for comp in self.components:
entityDf = X[(X[self.columns] == comp['id']).sum(axis=1) == len(self.columns)].copy()
res = comp['component'].predict(entityDf)
results.append(res)
dfRes = pd.concat(results)
return dfRes
def score(self, X, y=None, sample_weight=None):
results = []
for comp in self.components:
entityDf = X[(X[self.columns] == comp['id']).sum(axis=1) == len(self.columns)].copy()
if len(entityDf) > 0:
results.append(comp['component'].score(entityDf))
return np.average(results)
#create the input dataframe: 3 entities
dataFrame = pd.DataFrame([], columns=['entityId', 'input', 'output'])
for entity in range(3):
x = np.arange(random.randint(10, 20))
y = x * (entity + 1)
tempDf = pd.DataFrame(np.array([x, y]).T, columns=['input', 'output'])
tempDf['entityId'] = entity
dataFrame = pd.concat([dataFrame, tempDf], sort=False)
dataFrame = dataFrame.reset_index(drop=True)
#create the pipeline
neurons = [5, 10]
myPipe = Pipeline([('preTrain',
MyRegressor(neurons=neurons[0], featInput=['input'], featOutput=['output'])),
('fineTuning',
LoopTransformer(['entityId'],
MyRegressor(
neurons=neurons[0],
featInput=['input'],
featOutput=['output'])))])
#pre-train and fine-tuning has to have always the same number of neurons
params = [{
'preTrain__neurons': [neurons[0]],
'fineTuning__component__neurons': [neurons[0]]
}, {
'preTrain__neurons': [neurons[1]],
'fineTuning__component__neurons': [neurons[1]]
}]
gs = GridSearchCV(myPipe, params, verbose=1, cv=3)
gs.fit(dataFrame, dataFrame)
score = gs.score(dataFrame, dataFrame)
print(score)发布于 2019-01-07 16:04:28
我是一个漂亮的sklearn.Pipeline,因为它不支持这个。但是,只要您不克隆管道(例如,如果您使用一个GridSearchCV),您就可以通过下面这样的代码黑进一段代码,该代码将管道中的一个步骤的实例提供给下一个步骤。您可以在管道中应用相同的原则:
from sklearn.pipeline import make_pipeline
from sklearn.linear_model import LogisticRegression
from sklearn.preprocessing import StandardScaler
from sklearn.datasets import load_iris
from sklearn.base import BaseEstimator, TransformerMixin
class MyTransformer(BaseEstimator, TransformerMixin):
def __init__(self, scaler):
self.scaler = scaler
def fit(self, X, y=None):
print("got the means: %s" % self.scaler.mean_)
return self
def transform(self, X):
return X
X, y = load_iris(return_X_y=True)
scaler = StandardScaler()
pipeline = make_pipeline(scaler,
MyTransformer(scaler),
LogisticRegression(solver='lbfgs',
multi_class='auto'))
pipeline = pipeline.fit(X, y)
X = X - 1
pipeline = pipeline.fit(X, y)这将为您提供这个输出,正如预期的那样:
got the means: [5.84333333 3.05733333 3.758 1.19933333]
got the means: [4.84333333 2.05733333 2.758 0.19933333]https://stackoverflow.com/questions/54077325
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