我试图估计Weibull-Gamma分布参数,但遇到了以下错误:
函数mle无法估计参数,错误代码为7
我做什么好?
威布尔-伽玛分布
密度函数
dWeibullGamma <- function(x, alpha, beta, lambda)
{
((alpha*beta)/(lambda))*(x^(alpha-1))*(1+(1/lambda)*x^(alpha))^(-(beta+1))
}累积分布函数
pWeibullGamma <- function(x, alpha, beta, lambda)
{
1-(1+(1/lambda)*x^(alpha))^(-(beta))
}危害函数
hWeibullGamma <- function(x, alpha, beta, lambda)
{
((alpha*beta)/(lambda))*(x^(alpha-1))*(1+(1/lambda)*x^(alpha))^(-(beta+1))/(1+(1/lambda)*x^(alpha))^(-(beta))
}生存函数
sWeibullGamma <- function(x,alpha,beta,lambda)
{
(1+(1/lambda)*x^(alpha))^(-(beta))
}估计值
paramWG = fitdist(data = dadosp, distr = 'WeibullGamma', start = c(alpha=1.5,beta=1,lambda=1.5), lower= c(0, 0))
summary(paramWG)

Sample:
dadosp = c(240.3,71.9,271.3, 186.3,241,253,287.4,138.3,206.9,176,270.4,73.3,118.9,203.1,139.7,31,269.6,140.2,205.1,133.2,107,354.6,277,27.6,186,260.9,350.4,242.6,292.5, 112.3,242.8,310.7,309.9,53.1,326.5,145.7,271.5, 117.5,264.7,243.9,182,136.7,103.8,188.3,236,419.8,338.6,357.7)发布于 2018-10-10 09:32:49
对于您的示例,该算法在估计ML时不收敛。将威布尔-伽玛分布拟合到这些数据需要极高的lambda值。您可以通过估计log10(lambda)而不是lambda来解决这个问题。
您可以在您的4个函数中添加lambda <- 10^lambda。
dWeibullGamma <- function(x, alpha, beta, lambda)
{
lambda <- 10^lambda
((alpha*beta)/(lambda))*(x^(alpha-1))*(1+(1/lambda)*x^(alpha))^(-(beta+1))
}然后,该算法似乎收敛:
library(fitdistrplus)
paramWG = fitdist(data = data, distr = 'WeibullGamma',
start = list(alpha=1, beta=1, lambda=1), lower = c(0, 0, 0))
summary(paramWG)$estimate输出:
alpha beta lambda
2.432939 799.631852 8.680802 我们发现lambda的估计是10^8.68的,因此在不取日志的情况下出现了收敛问题。
您还可以从以下几个方面查看合适的内容:
newx <- 0:500
pars <- summary(paramWG)$estimate
pred <- dWeibullGamma(newx, pars["alpha"], pars["beta"], pars["lambda"])
hist(data, freq = FALSE)
lines(newx, pred, lwd = 2)

注:也许适合另一个分布会更有意义?
https://stackoverflow.com/questions/52721871
复制相似问题