异常处理，并在python中继续使用for循环

Question

我有以下代码：

import Bio
from bioservices import KEGGParser, UniProt, QuickGO

#start a new method of my custom 'Retrieve_Data' class
def locate_common_GO(self,list_of_genes,GO_term):
    
    #initialize variables and classes
    q = QuickGO()
    a = Retrieve_Data()
    b=[]

使用(自定义方法) hugo2uniprot获取uniprot

for i in range(0,len(list_of_genes)):
    b.append(a.hugo2uniprot(list_of_genes[i],'hsa'))
    print 'Gene: {} \t UniProtID: {}'.format(list_of_genes[i],b[i])

搜索GO术语(使用bioservices‘QuickGO)并存储为字典

GO_dict = {}
q = QuickGO()

一些大的基因名称，我没有返回任何点击。这些导致了我想要处理的AttributeError，然后转到列表中的下一项。当前代码返回错误：

AttributeError：'int‘对象没有属性’拆分‘。

错误起源于bioservices模块(所以当我调用q.Annotation时)

for i in range(len(b)):
    try:
        GO_dict[list_of_genes[i]] = q.Annotation(protein=b[i], frmt="tsv", _with=True,tax=9606, source="UniProt", col="goName")
    except AttributeError:
        continue

# The rest of this code is irrelevant to my problem but I've included it for completeness: 
# Essentially it is designed to locate specific keywords in the results of the above code and return the gene name that they came from. 
keys = GO_dict.keys()
matches = []
for gene in range(0,len(keys)):
    if GO_term in GO_dict[keys[gene]].splitlines():
        matches.append(keys[gene])
return matches

有没有人建议让异常处理工作，这样它就可以完成对指定列表的迭代，而不是停止脚本？

Answer 1

好吧，我刚刚意识到问题是错误来自不同的代码.所以我基本上什么都没处理。我现在已经修好了，多亏了所有的回应。