RQ作业排队但未运行

Question

我在Python-RQ的作业排队方面有问题，作业似乎排队很好，但它们没有运行、崩溃或任何他们必须做的事情。

我正在做的过程如下：

1. 在本地主机上运行redis服务器：

loren@RONDAN1:/mnt/c/Users/rondan$ sudo service redis-server restart
[sudo] password for loren:
Stopping redis-server: redis-server.
Starting redis-server: redis-server.
loren@RONDAN1:/mnt/c/Users/rondan$ rq info
default      | 0
1 queues, 0 jobs total

72a81f7d4cde4e7c865b178772766aef (RONDAN1 95): idle default
1 workers, 1 queues

Updated: 2021-03-16 19:26:52.459427

1. 在其他bash上运行员工：

loren@RONDAN1:/mnt/c/Users/rondan$ rq worker --with-scheduler
19:26:42 Worker rq:worker:72a81f7d4cde4e7c865b178772766aef: started, version 1.7.0
19:26:42 Subscribing to channel rq:pubsub:72a81f7d4cde4e7c865b178772766aef
19:26:42 *** Listening on default...
19:26:42 Trying to acquire locks for default
19:26:42 Scheduler for default started with PID 98
19:26:42 Cleaning registries for queue: default

1. 运行我的python演示代码(此代码在异步方式中不使用redis队列)：

main.py

import lightquery as lq
from datetime import datetime, timedelta
import time
from redis import Redis
from rq import Queue

queue = Queue(connection=Redis())


def queue_tasks():
    queue.enqueue(lq.print_task, 5)
    queue.enqueue_in(timedelta(seconds=10), lq.print_numbers, 5)


def main():
    queue_tasks()

if __name__ == "__main__":
    main()

lightquery.py

import time

def print_task(seconds):
    print("Starting task")
    for num in range(seconds):
        print(num, ". Hello World!")
        time.sleep(1)
    print("Task completed")


def print_numbers(seconds):
    print("Starting num task")
    for num in range(seconds):
        print(num)
        time.sleep(1)
    print("Task to print_numbers completed")

1. 运行代码后，执行将正确结束，作业将排队：

loren@RONDAN1:/mnt/c/Users/rondan$ rq worker --with-scheduler
19:26:42 Worker rq:worker:72a81f7d4cde4e7c865b178772766aef: started, version 1.7.0
19:26:42 Subscribing to channel rq:pubsub:72a81f7d4cde4e7c865b178772766aef
19:26:42 *** Listening on default...
19:26:42 Trying to acquire locks for default
19:26:42 Scheduler for default started with PID 98
19:26:42 Cleaning registries for queue: default
19:28:43 default: lightquery.print_task(5) (02a07849-64b5-4f44-8e0b-89bb466110ee)

在将作业添加到作业后，我尝试显示作业队列，并打印一个空数组(也许这可以帮助您给出解决方案)。

编辑的

loren@RONDAN1:/mnt/c/Users/rondan$ sudo service redis-server restart
Stopping redis-server: redis-server.
Starting redis-server: redis-server.
loren@RONDAN1:/mnt/c/Users/rondan$ rq info
default      | 0
1 queues, 0 jobs total

0 workers, 1 queues

Updated: 2021-03-17 07:59:13.587043
loren@RONDAN1:/mnt/c/Users/rondan$

loren@RONDAN1:/mnt/c/Users/rondan$ rq worker --with-scheduler
08:00:15 Worker rq:worker:b1fcdaaf1c224e239d28f9fdf8509a1a: started, version 1.7.0
08:00:15 Subscribing to channel rq:pubsub:b1fcdaaf1c224e239d28f9fdf8509a1a
08:00:15 *** Listening on default...
08:00:15 Trying to acquire locks for default
08:00:15 Scheduler for default started with PID 65
08:00:15 Cleaning registries for queue: default

loren@RONDAN1:/mnt/c/Users/rondan$ rq info
default      | 0
1 queues, 0 jobs total

b1fcdaaf1c224e239d28f9fdf8509a1a (RONDAN1 62): idle default
1 workers, 1 queues

Updated: 2021-03-17 08:02:29.590837

Answer 1

问题是我导入模块的方式..。

使用

from lightquery import print_task
...
queue.enqueue(print_task, 5)

而不是：

import lightquery as lq
...
queue.enqueue(lq.print_task(), 5)