错误:已经在generate构造之外找到了generate /end对

Question

我才刚开始学习Verilog。我一直在尝试理解<=的操作顺序。我明白它的作用，但我正在试图找出它的范围。我假设下面的代码将是一个很好的示例来处理这个问题，但是当我在Model Sim中编译它时，我会得到以下错误。

** Error (suppressible): /Documents/SystemVerilog2.sv(48): (vlog-2720) A generate begin/end pair has been found outside of generate construct.
** Error: (vlog-13069): /SystemVerilog2.sv(111): near "(": syntax error, unexpected '('.

这就是我想要运行的代码。我不知道如何处理这些错误。

module tutorial_led_blink 
  (
   i_clock,
   i_enable,
   i_switch_1,
   i_switch_2,
   o_led_drive
   );
 
  input i_clock;
  input i_enable;
  input i_switch_1;
  input i_switch_2;
  output o_led_drive;
    
  // Constants (parameters) to create the frequencies needed:
  // Input clock is 25 kHz, chosen arbitrarily.
  // Formula is: (25 kHz / 100 Hz * 50% duty cycle)
  // So for 100 Hz: 25,000 / 100 * 0.5 = 125
  parameter c_CNT_100HZ = 125;
  parameter c_CNT_50HZ  = 250;
  parameter c_CNT_10HZ  = 1250;
  parameter c_CNT_1HZ   = 12500;
 
  // These signals will be the counters:
  reg [31:0] r_CNT_100HZ = 0;
  reg [31:0] r_CNT_50HZ = 0;
  reg [31:0] r_CNT_10HZ = 0;
  reg [31:0] r_CNT_1HZ = 0;
   
  // These signals will toggle at the frequencies needed:
  reg        r_TOGGLE_100HZ = 1'b0;
  reg        r_TOGGLE_50HZ  = 1'b0;
  reg        r_TOGGLE_10HZ  = 1'b0;
  reg        r_TOGGLE_1HZ   = 1'b0;
   
  // One bit select
  reg        r_LED_SELECT;
  wire       w_LED_SELECT;
   
     
begin
 
  // All always blocks toggle a specific signal at a different frequency.
  // They all run continuously even if the switches are
  // not selecting their particular output.
 
  always @ (posedge i_clock)
    begin
      if (r_CNT_100HZ == c_CNT_100HZ-1) // -1, since counter starts at 0
        begin        
          r_TOGGLE_100HZ <= !r_TOGGLE_100HZ;
          r_CNT_100HZ    <= 0;
        end
      else
        r_CNT_100HZ <= r_CNT_100HZ + 1;
    end
 
   
  always @ (posedge i_clock)
    begin
      if (r_CNT_50HZ == c_CNT_50HZ-1) // -1, since counter starts at 0
        begin        
          r_TOGGLE_50HZ <= !r_TOGGLE_50HZ;
          r_CNT_50HZ    <= 0;
        end
      else
        r_CNT_50HZ <= r_CNT_50HZ + 1;
    end
 
 
  always @ (posedge i_clock)
    begin
      if (r_CNT_10HZ == c_CNT_10HZ-1) // -1, since counter starts at 0
        begin        
          r_TOGGLE_10HZ <= !r_TOGGLE_10HZ;
          r_CNT_10HZ    <= 0;
        end
      else
        r_CNT_10HZ <= r_CNT_10HZ + 1;
    end
 
   
  always @ (posedge i_clock)
    begin
      if (r_CNT_1HZ == c_CNT_1HZ-1) // -1, since counter starts at 0
        begin        
          r_TOGGLE_1HZ <= !r_TOGGLE_1HZ;
          r_CNT_1HZ    <= 0;
        end
      else
        r_CNT_1HZ <= r_CNT_1HZ + 1;
    end
 
  // Create a multiplexer based on switch inputs
  always @ (*)
  begin
    case ({i_switch_1, i_switch_2}) // Concatenation Operator { }
      2'b11 : r_LED_SELECT <= r_TOGGLE_1HZ;
      2'b10 : r_LED_SELECT <= r_TOGGLE_10HZ;
      2'b01 : r_LED_SELECT <= r_TOGGLE_50HZ;
      2'b00 : r_LED_SELECT <= r_TOGGLE_100HZ;
    endcase     
  end
 
  assign o_led_drive = r_LED_SELECT & i_enable;
 
  // Alternative way to design multiplexer (same as above):
  // More compact, but harder to read, especially to those new to Verilog
  // assign w_LED_SELECT = i_switch_1 ? (i_switch_2 ? r_TOGGLE_1HZ : r_TOGGLE_10HZ) : 
                                        (i_switch_2 ? r_TOGGLE_50HZ : r_TOGGLE_100HZ);
  // assign o_led_drive = w_LED_SELECT & i_enable;
     
   
end
   
endmodule

Answer 1

去掉第一个begin和最后一个end。您的always块和assign语句不需要被begin/end封装。这就是“生成开始/结束”错误消息试图告诉您的内容。

参见IEEE Std 1800-2017，第27节。生成构造。