我有下面的bash脚本,我想把它转换成一个snakefile:
mmseqs rbh flye_db megahit_db flye_megahit_rbh --min-seq-id 0.9 mmseq2_tmp --threads 12
mmseqs rbh flye_db metaspades_db flye_metaspades_rbh --min-seq-id 0.9 mmseq2_tmp --threads 12
mmseqs rbh megahit_db metaspades_db megahit_metaspades_rbh --min-seq-id 0.9 mmseq2_tmp --threads 12我已经想出了以下内容,但我想知道是否有一种方法可以使用regex或展开来进一步改进代码:
rule mmseq2_compare:
input:
mm1=expand(os.path.join(RESULTS_DIR, "annotation/mmseq2/{assembler}_db"), assembler="flye"),
mm2=expand(os.path.join(RESULTS_DIR, "annotation/mmseq2/{assembler}_db"), assembler="megahit"),
mm3=expand(os.path.join(RESULTS_DIR, "annotation/mmseq2/{assembler}_db"), assembler="metaspades_hybrid")
output:
mo1=os.path.join(RESULTS_DIR, "annotation/mmseq2/flye_megahit_rbh"),
mo2=os.path.join(RESULTS_DIR, "annotation/mmseq2/flye_metaspades_hybrid_rbh"),
mo3=os.path.join(RESULTS_DIR, "annotation/mmseq2/megahit_metaspades_hybrid_rbh")
log: os.path.join(RESULTS_DIR, "annotation/mmseq2/compare.mmseq2.log")
conda: "cd-hit.yml"
shell:
"""
(date &&\
mmseqs rbh {input.mm1} {input.mm2} {output.mo1} --min-seq-id 0.9 mmseq2_tmp --threads 12 &&\
mmseqs rbh {input.mm1} {input.mm3} {output.mo2} --min-seq-id 0.9 mmseq2_tmp --threads 12 &&\
mmseqs rbh {input.mm2} {input.mm3} {output.mo3} --min-seq-id 0.9 mmseq2_tmp --threads 12 &&\
date) &> >(tee {log})
"""有了三个汇编程序(flye,megahit和metaspades_hybrid),有没有办法消除冗余,特别是在“shell”中?
谢谢!
试运行输出
Building DAG of jobs...
Job counts:
count jobs
1 all
1 mmseq_compare
2
[Thu Mar 26 12:25:14 2020]
rule mmseq_compare:
input: results/annotation/mmseq2/flye_db, results/annotation/mmseq2/megahit_db
output: results/annotation/mmseq2/flye_megahit_rbh
jobid: 1
wildcards: assembler1=flye, assembler2=megahit
mmseqs rbh results/annotation/mmseq2/flye_db results/annotation/mmseq2/megahit_db results/annotation/mmseq2/flye_megahit_rbh --min-seq-id 0.9 mmseq2_tmp --threads 12
[Thu Mar 26 12:25:14 2020]
localrule all:
input: results/annotation/mmseq2/flye_megahit_rbh, results/annotation/mmseq2/flye_metaspades_hybrid_rbh, results/annotation/mmseq2/megahit_metaspades_hybrid_rbh
jobid: 0
Job counts:
count jobs
1 all
1 mmseq_compare
2
This was a dry-run (flag -n). The order of jobs does not reflect the order of execution.```发布于 2020-03-25 23:59:36
首先,您在输入中不需要expand。如果希望创建具有相同模式的文件名列表,则需要这样做。
接下来,只要您已经在路径中使用Unix类型的斜杠,就可以将RESULTS_DIR添加到f-字符串中以提高可读性(但不要忘记将通配符的大括号加倍)。
最后,没有必要将脚本管道与&&:分隔开来,这正是Snakemake设计的目的。
我的重编脚本版本:
rule all:
input:
expand(f"{RESULTS_DIR}/annotation/mmseq2/{{assembler1}}__{{assembler2}}_rbh", zip,
assembler1=["flye", "flye", "megahit"],
assembler2=["megahit", "megahit_metaspades_hybrid", "megahit_metaspades_hybrid"])
rule mmseq_compare:
input:
f"{RESULTS_DIR}/annotation/mmseq2/{{assembler1}}_db",
f"{RESULTS_DIR}/annotation/mmseq2/{{assembler2}}_db"
output:
f"{RESULTS_DIR}/annotation/mmseq2/{{assembler1}}__{{assembler2}}_rbh"
conda:
"cd-hit.yml"
shell:
"mmseqs rbh {input[0]} {input[1]} {output} --min-seq-id 0.9 mmseq2_tmp --threads 12"我已经排除了date和日志记录。我的解决方案有一个限制,即比较的执行顺序没有定义:在这种情况下,您需要重新考虑日志策略。
https://stackoverflow.com/questions/60854079
复制相似问题