我正试图从Rust中调用Btrieve (一个非常老的数据库引擎)。这有点长,但这是我第一次尝试FFI从锈,我想描述我所做的一切。
Btrieve引擎在DLL中实现,w3btrv7.dll是32位DLL。我使用32位MSVC工具为它创建了一个导入库(它没有附带正式的):
lib /Def:w3btrv7.def /Out:w3btrv7.lib /Machine:x86然后,我安装了32位锈蚀工具链stable-i686-pc-windows-msvc,并将其设置为我的默认设置。Bindgen在官方的Btrieve头球上乱翻,所以我不得不自己做。幸运的是,我们只需要包装一个函数,BTRCALL。
我的包装纸里有这个
short int BTRCALL(
unsigned short operation,
void* posBlock,
void* dataBuffer,
unsigned short* dataLength,
void* keyBuffer,
unsigned char keyLength,
char ckeynum);我的联系是:
println!("cargo:rustc-link-lib=./src/pervasive/w3btrv7");这似乎是可行的:程序运行,是一个32位的exe,我可以在Process中看到它已经加载了w3btrv7.dll。
当我通过bindgen发送标头时,我得到:
extern "C" {
pub fn BTRCALL(
operation: ::std::os::raw::c_ushort,
posBlock: *mut ::std::os::raw::c_void,
dataBuffer: *mut ::std::os::raw::c_void,
dataLength: *mut ::std::os::raw::c_ushort,
keyBuffer: *mut ::std::os::raw::c_void,
keyLength: ::std::os::raw::c_uchar,
ckeynum: ::std::os::raw::c_char,
) -> ::std::os::raw::c_short;
}类型和大小似乎都是正确的,它们与我从C#应用程序中获得的一个完美工作的C#相匹配:
[DllImport("w3btrv7.dll", CharSet = CharSet.Ansi)]
private static extern short BTRCALL(
ushort operation, // In C#, ushort = UInt16.
[MarshalAs(UnmanagedType.LPArray, SizeConst = 128)] byte[] posBlock,
[MarshalAs(UnmanagedType.LPArray)] byte[] dataBuffer,
ref ushort dataLength,
[MarshalAs(UnmanagedType.LPArray)] byte[] keyBuffer,
byte keyLength, // unsigned byte
char keyNumber); // 2 byte charkeyNumber略有不同,但我尝试过有符号变体和无符号变体中的字节和空号,但仍然无法工作。
不幸的是,当我运行我的程序时,它在第一次调用BTRCALL之后就会崩溃。(实际上,这个调用是在返回函数时进行的)。我已经将所有参数提取到局部变量中,并检查了它们的类型,并且看起来都是正确的:
let op: u16 = 0;
let mut pos_block: [u8; 128] = self.pos_block.clone();
let pos_block_ptr: *mut std::ffi::c_void = pos_block.as_mut_ptr() as *mut _;
let mut data_buffer: [u8; 32768] = self.data_buffer.clone();
let data_buffer_ptr: *mut std::ffi::c_void = data_buffer.as_mut_ptr() as *mut _;
let mut data_length: u16 = data_buffer.len() as u16;
let mut key_buffer: [u8; 256] = self.key_buffer.clone();
let key_buffer_ptr: *mut std::ffi::c_void = key_buffer.as_mut_ptr() as *mut _;
let key_length: u8 = 255; //self.key_length;
let key_number: i8 = self.key_number.try_into().unwrap();
let status: i16 = BTRCALL(
op,
pos_block_ptr,
data_buffer_ptr,
&mut data_length,
key_buffer_ptr,
key_length,
key_number
);它使程序崩溃
error: process didn't exit successfully: `target\debug\blah.exe` (exit code: 0xc0000005, STATUS_ACCESS_VIOLATION)据我所读,这可能是由于不正确的地址访问。
实际上,当我输入一些跟踪来检查变量时,有一些非常有趣的行为,因为被值传递的局部变量似乎被覆盖了。这里的日志只是转储缓冲的前30个字节,因为剩下的只是零:
pos_block = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
pos_block_ptr = 0xad6524
data_buffer = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
data_buffer_ptr = 0xad65a8
data_length = 32768
key_buffer = [34, 67, 58, 92, 116, 101, 109, 112, 92, 99, 115, 115, 92, 120, 100, 98, 92, 67, 65, 83, 69, 46, 68, 66, 34, 0, 0, 0, 0, 0]
key_buffer_ptr = 0xade5b0
key_length = 255
key_number = 0
>>>>>>>>>>>>>>> AFTER THE CALL TO BTRCALL:
pos_block = [0, 0, 0, 0, 0, 0, 0, 0, 0, 76, 203, 0, 0, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 0, 0, 0, 0, 0]
pos_block_ptr = 0x0
data_buffer = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
data_buffer_ptr = 0x42442e45
data_length = 0
key_buffer = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
key_buffer_ptr = 0x0
key_length = 173
key_number = 0
BTRCALL() returned B_NO_ERROR注意,除其他外,pos_block_ptr已设置为0。相反,成功地执行来自C#代码的完全相同的调用,只需将一些数据写入pos_block的前18个字节,而不改变任何其他变量。
好像有点狂暴开始覆盖记忆.
在这一点上,我不知道下一步该尝试什么。
发布于 2020-01-01 17:28:51
将声明从extern "C"更改为extern "stdcall"工作:
extern "stdcall" {
pub fn BTRCALL(
operation: ::std::os::raw::c_ushort,
posBlock: *mut ::std::os::raw::c_void,
dataBuffer: *mut ::std::os::raw::c_void,
dataLength: *mut ::std::os::raw::c_ushort,
keyBuffer: *mut ::std::os::raw::c_void,
keyLength: ::std::os::raw::c_uchar,
ckeynum: ::std::os::raw::c_char,
) -> ::std::os::raw::c_short;
}https://stackoverflow.com/questions/59554267
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