Keras中的凹凸不平的数组

Question

我有几个要连接的RaggedTensors；我使用的是Keras。Vanilla Tensorflow会很高兴地将它们连接起来，所以我尝试了下面的代码：

card_feature = layers.concatenate([ragged1, ragged2, ragged3])

但它给出了一个错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/timeroot/.local/lib/python3.8/site-packages/tensorflow/python/keras/engine/base_layer.py", line 925, in __call__
    return self._functional_construction_call(inputs, args, kwargs,
  File "/home/timeroot/.local/lib/python3.8/site-packages/tensorflow/python/keras/engine/base_layer.py", line 1084, in _functional_construction_call
    base_layer_utils.create_keras_history(inputs)
  File "/home/timeroot/.local/lib/python3.8/site-packages/tensorflow/python/keras/engine/base_layer_utils.py", line 191, in create_keras_history
    _, created_layers = _create_keras_history_helper(tensors, set(), [])
  File "/home/timeroot/.local/lib/python3.8/site-packages/tensorflow/python/keras/engine/base_layer_utils.py", line 222, in _create_keras_history_helper
    raise ValueError('Tensorflow ops that generate ragged or sparse tensor '
ValueError: Tensorflow ops that generate ragged or sparse tensor outputs are currently not supported by Keras automatic op wrapping. Please wrap these ops in a Lambda layer: 

  weights_mult = lambda x: tf.sparse.sparse_dense_matmul(x, weights)

  output = tf.keras.layers.Lambda(weights_mult)(input)

于是我试着：

concat_lambda = lambda xs: tf.concat(xs, axis=2)
card_feature = layers.Lambda(concat_lambda)([ragged1, ragged2, ragged3])

但它给出了完全相同的错误，即使我已经包装了它。这是错误/有解决办法吗？

Answer 1

连接3 Ragged Tensors的代码如下所示：

import tensorflow as tf

print(tf.__version__)

Ragged_Tensor1 = tf.ragged.constant([[3, 1, 4, 1], [], [5, 9, 2], [6], []])
Ragged_Tensor2 = tf.ragged.constant([[5, 3]])
Ragged_Tensor3 = tf.ragged.constant([[6,7,8], [9,10]])
print(tf.concat([Ragged_Tensor1, Ragged_Tensor2, Ragged_Tensor3], axis=0))

产出如下：

2.3.0
<tf.RaggedTensor [[3, 1, 4, 1], [], [5, 9, 2], [6], [], [5, 3], [6, 7, 8], [9, 10]]>

但看起来你是在尝试连接破烂的张量操作。请分享您的完整代码，以便我们可以尝试帮助您。