如何连续地将数据从全双工双口SRAM的端口放到端口？

Question

在一个全双工双口SRAM中，我试图读取数据并将数据从A端口写入B端口，而无需等待时间。

    module tb_fbdp_ram();
    
        // Define our controlled signals
        reg clk=0;
        reg cs=0;
        reg a_we, a_oe, b_we=0, b_oe=1;
        wire [7:0] a_data;     // this is the connection to ramcu data port
        reg [7:0] a_addr=0;     // this is the address for port A
        wire [7:0] b_data;     // this is the connection to ramcu data port
        reg [7:0] b_addr=0;     // this is the address for port A
    
        reg  [7:0] a_data_value; // need a register to store value to send on a write
        reg  [7:0] b_data_value; // need a register to store value to send on a write
    
        // Instantiate our DUT
        fbdp_ram dut (
            clk     , // clock input
            cs      , // chip select
            a_we    , // channel A write enable
            a_oe    , // channel A output enable
            a_addr  , // channel A address
            a_data  , // channel A inout data
            b_we    , // channel B write enable
            b_oe    , // channel B output enable
            b_addr  , // channel B address
            b_data    // channel B inout data
    );
    
    assign a_data = !a_oe ? a_data_value : 'bz;
    assign b_data = !b_oe ? b_data_value : 'bz;
    
    
    always #5 clk = ~clk;
    
    
    initial begin


    for(int i=0; i< 15; i++) begin
    @(posedge clk);
    // set up initial conditions
    cs      = 1;
    a_we    = 1;
    a_oe    = 0;
    a_addr  = i;
    a_data_value = $urandom%10;
    end
    // set up initial conditions
    for(int i=0; i< 15; i++) begin
    @(posedge clk);
    cs      = 1;
    a_we    = 0;
    a_oe    = 1;
    a_addr  = i;

    b_we    = 1;
    b_oe    = 0;
    b_addr  = i+20;
    b_data_value = a_data;
    end
end

我从A端口读取一些数据，并立即将它们写入B端口。但是，来自A端口的B端口的输入数据延迟了一个时钟。

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如图中所示，'h08值被放入B端口的数据，而不是'h09。我怎么写“h09而不是”h08呢？

Answer 1

首先删除行b_data_value = a_data;

在testbench的末尾，在任何其他块之外，添加：

assign b_data_value = a_data;

例如：

  // ...
  // ...
  // set up initial conditions
  for(int i=0; i< 15; i++) begin
    @(posedge clk);
    cs      = 1;
    a_we    = 0;
    a_oe    = 1;
    a_addr  = i;

    b_we    = 1;
    b_oe    = 0;
    b_addr  = i+20;
  end
  // combinatorially assign to ensure instantaneous writing to b_data
  assign b_data_value = a_data;
end