如何解决Serde反序列化的终身错误？

Question

目标：--我希望实现这个特性，而不会出现终身错误。

依赖关系：pqcrypto-dilithium = "0.4.5"和serde = {version = "1.0.138", features = ["derive"]}。在Cargo.toml中导入这个

进口：

pub use pqcrypto_dilithium::dilithium5::*;
pub use pqcrypto_dilithium::dilithium5::DetachedSignature;
pub use serde::ser::{SerializeTuple};
pub use serde::de::Visitor;
pub use serde::{Serialize, Serializer, Deserialize, Deserializer};

Seriaize实现功能正常，但反序列化实现存在生存期问题。

#[derive(Serialize, Deserialize)]
pub struct Keys {
    pub public_key: pqcrypto_dilithium::dilithium5::PublicKey,
    pub private_key: pqcrypto_dilithium::dilithium5::SecretKey,
}

impl Serialize for Keys {
    fn serialize<S>(&self, serializer: &mut S) -> Result<S::Ok, S::Error>
        where S: Serializer
    {
        let mut state = serializer.serialize_tuple(2)?;
        state.serialize_element(&self.public_key)?;
        state.serialize_element(&self.private_key)?;
        state.end()
    }
}

impl Deserialize<'de> for Keys {
fn deserialize<D>(deserializer: &mut D) -> Result<Self, D::Error>
    where D: Deserializer<'de>
{
    deserializer.deserialize_tuple(2, Visitor)
}
}

这里的问题在于Keys的反序列化实现。我得到了这个错误。

use of undeclared lifetime name `'de`
undeclared lifetimerustcE0261
crypto.rs(36, 5): consider introducing lifetime `'de` here: `<'de>`
crypto.rs(37, 20): consider introducing lifetime `'de` here: `'de, `
[E0261] use of undeclared lifetime name `'de`. 
[Note] undeclared lifetime

Answer 1

正确答案：

impl <'de> Deserialize<'de> for Keys {
    fn deserialize<D>(deserializer: &mut D) -> Result<Self, D::Error>
        where D: Deserializer<'de>...