这是我提出的另一个问题的延续:Instanciation of a class doesn't work (Chisel/Scala)
实际上,我想打印“结果”变量。我编写了以下命令: sbt测试,我不理解这个错误:
"chisel3.internal.ChiselException:无法重新分配到只读组合Tausworthe.b: OpResultUInt<32>“
这是测试文件
import chiseltest._
import org.scalatest.freespec.AnyFreeSpec
class combined_test extends AnyFreeSpec with ChiselScalatestTester {
"combinedTauswhore" in {
test(new combinedTausworthe() ){ c =>
//Initialisation
c.clock.step(1)
println(c.result)
c.clock.step(1)
println(c.result)
}
}
}这是一堂课:
import chisel3._
class combinedTausworthe extends Module{
val io = IO(new Bundle {
})
val seed1 = RegInit(322769304.U(32.W))
val seed2 = RegInit(424235419.U(32.W))
val seed3 = RegInit(212119443.U(32.W))
var result= 0.U
var b = ((seed1 << 13)(31,0) ^ seed1)
seed1 := ((seed1 & 4294967294L.U) << 12)(31,0) ^ b
b := ((seed2 << 2)(31,0) ^ seed2) >> 25
seed2 := ((seed2 & 4294967294L.U) << 4)(31,0) ^ b
b := ((seed3<<3)(31,0) ^ seed3) >> 11
seed3 := ((seed3 & 4294967294L.U) <<17)(31,0) ^ b
result := (seed1 ^ seed2 ^ seed3)
}
object Main extends App {
}发布于 2022-05-18 20:22:30
在Chisel3中,:=是驱动具有某种值的信号的连接操作符。把它想成是制造一种电气连接。在您的代码中,您似乎试图将变量重新分配到可变变量,而不是使用值驱动该变量的值,尝试=。
import chisel3._
class combinedTausworthe extends Module{
val io = IO(new Bundle {
})
val seed1 = RegInit(322769304.U(32.W))
val seed2 = RegInit(424235419.U(32.W))
val seed3 = RegInit(212119443.U(32.W))
var result= 0.U
var b = ((seed1 << 13)(31,0) ^ seed1)
seed1 := ((seed1 & 4294967294L.U) << 12)(31,0) ^ b
// Note using assignment (=), not connection (:=)
b = ((seed2 << 2)(31,0) ^ seed2) >> 25
seed2 := ((seed2 & 4294967294L.U) << 4)(31,0) ^ b
b = ((seed3<<3)(31,0) ^ seed3) >> 11
seed3 := ((seed3 & 4294967294L.U) <<17)(31,0) ^ b
// Same thing here
result = (seed1 ^ seed2 ^ seed3)
}尽管如此,由于Scala是一种函数式编程语言,我们在风格上更喜欢纯/不变的结构,所以只使用值:
import chisel3._
class combinedTausworthe extends Module{
val io = IO(new Bundle {
})
val seed1 = RegInit(322769304.U(32.W))
val seed2 = RegInit(424235419.U(32.W))
val seed3 = RegInit(212119443.U(32.W))
// Note result var removed and replaced with val below
val b1 = ((seed1 << 13)(31,0) ^ seed1)
seed1 := ((seed1 & 4294967294L.U) << 12)(31,0) ^ b1
val b2 = ((seed2 << 2)(31,0) ^ seed2) >> 25
seed2 := ((seed2 & 4294967294L.U) << 4)(31,0) ^ b2
val b3 = ((seed3<<3)(31,0) ^ seed3) >> 11
seed3 := ((seed3 & 4294967294L.U) <<17)(31,0) ^ b3
val result = (seed1 ^ seed2 ^ seed3)
}https://stackoverflow.com/questions/72295386
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