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functional API测试失败
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Stack Overflow用户
提问于 2019-05-19 02:23:39
回答 1查看 21关注 0票数 0

为了进行测试,我尝试将https://colab.research.google.com/github/tensorflow/docs/blob/master/site/en/r2/tutorials/generative/dcgan.ipynb#scrollTo=6bpTcDqoLWjY的生成器转换为functional API,但它不起作用。ValueError:使用序列设置数组元素。

有人知道我做错了什么吗?

我将生成器代码替换为:

代码语言:javascript
复制
def make_generator_model():
  inputs = tf.keras.Input(shape=(100,))

  l = layers.Dense(7*7*256, use_bias=False)(inputs)
  #l1 = layers.BatchNormalization(l)
  l2 = layers.LeakyReLU(l)
  l3 = layers.Reshape((7, 7, 256))(l2)
  l4 = layers.Conv2DTranspose(128, (5, 5), strides=(1, 1), padding='same', use_bias=False)(l3)
  #l5 = layers.BatchNormalization()(l4)
  l6 = layers.LeakyReLU()(l4)
  l7 = layers.Conv2DTranspose(64, (5, 5), strides=(2, 2), padding='same', use_bias=False)(l6)
  #l8 = layers.BatchNormalization()(l7)
  l9 = layers.LeakyReLU()(l7)
  l10 = layers.Conv2DTranspose(1, (5, 5), strides=(2, 2), padding='same', use_bias=False, activation='tanh')(l9)
  return tf.keras.Model(inputs=inputs, outputs=l10)
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回答 1

Stack Overflow用户

发布于 2019-05-19 16:45:29

错误来自于LeakyRely () ()之后缺少()。工作代码是:

代码语言:javascript
复制
def make_generator_model():
  inputs = tf.keras.Input(shape=(100,))

  l = layers.Dense(7*7*256, use_bias=False)(inputs)
  l1 = layers.BatchNormalization()(l)
  l2 = layers.LeakyReLU()(l1)
  l3 = layers.Reshape((7, 7, 256))(l2)
  l4 = layers.Conv2DTranspose(128, (5, 5), strides=(1, 1), padding='same', use_bias=False)(l3)
  l5 = layers.BatchNormalization()(l4)
  l6 = layers.LeakyReLU()(l5)
  l7 = layers.Conv2DTranspose(64, (5, 5), strides=(2, 2), padding='same', use_bias=False)(l6)
  l8 = layers.BatchNormalization()(l7)
  l9 = layers.LeakyReLU()(l8)
  l10 = layers.Conv2DTranspose(1, (5, 5), strides=(2, 2), padding='same', use_bias=False, activation='tanh')(l9)
  return tf.keras.Model(inputs=inputs, outputs=l10)
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56201737

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