如何开始使用python通过空格键移动乌龟

Question

我正在尝试用python创建一个简单的海龟程序，我可以通过按下空格键开始移动海龟，它会一直移动，直到我再次按下空格键。我可以让他用空格键移动一段固定的距离，但不能让它继续。

以下是我正在使用的内容：

from turtle import *


# PUT YOUR CODE HERE
setup(800,600)
home()
pen_size = 2
color("blue")
title("Turtle")
speed("fastest") 
drawdist= 25 
current_state = penup
next_state = pendown

#Button Instructions
def move_up():
        seth(90)
        forward(drawdist)

def move_down():
        seth(270)
        forward(drawdist)

def move_left():
        seth(180)
        forward(drawdist)

def move_right():
        seth(0)
        forward(drawdist)


def space_bar():
    seth(90)
    forward(drawdist)
    global current_state, next_state
    next_state()
    current_state, next_state = next_state, current_state

#Change Pen Color
def red():
        color("red")

def green():
        color("green")

def blue():
        color("blue")


#Button Triggers
s= getscreen()

s.onkey(move_up,"Up")

s.onkey(move_down,"Down")

s.onkey(move_left,"Left")

s.onkey(move_right,"Right")

s.onkey(space_bar,"space")

s.onkey(red,"r")

s.onkey(green,"g")

s.onkey(blue,"b")

listen()

done()

Answer 1

我不知道你的问题有没有答案：

开始按下空格键来移动乌龟，他一直在移动，直到我再次按下空格键

建议的onkeypress()修复不能做到这一点。这是一个简单的例子，它可以做你想做的，当你点击空格键时启动乌龟，当你再次点击空格键时停止它：

from turtle import Turtle, Screen

screen = Screen()
turtle = Turtle(shape="turtle")
turtle.speed("fastest")

def current_state():
    global moving
    moving = False
    turtle.penup()

def next_state():
    global moving
    turtle.pendown()
    moving = True
    move()

def space_bar():
    global current_state, next_state
    next_state()
    current_state, next_state = next_state, current_state

def move():
    if moving:
        turtle.circle(100, 3)
        screen.ontimer(move, 50)

current_state()

screen.onkey(space_bar, "space")

screen.listen()

screen.mainloop()

我在这个例子中使用了圆周运动，这样你就可以随意启动和停止乌龟了。

Answer 2

将函数'onkey‘替换为函数'onkeypress’。

不管按住这个键，'onkey‘函数都会触发一次，而'onkeypress’函数会触发，就像您按住这个键时所期望的那样。

Answer 3

正确且最简单的方法是这样(不是事件侦听器空格键，这只是事件侦听器)：

import turtle 
import random

t = turtle.Turtle()
screen = turtle.Screen(

def goForward():
  t.forward(input_value)

screen.onkey(goForward, "Forward")

hashtags中的" right“一词只表示按下正确的键。