我有一个很大的.csv文件,如下所示:
Transcript Id Gene Id(name) Mirna Name miTG score
ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1
UTR3 21:30717114-30717142 0.05994568
UTR3 21:30717414-30717442 0.13591267
ENST00000345080 ENSG00000187772 (LIN28B) hsa-let-7a-5p 1
UTR3 6:105526681-105526709 0.133514751 我想用它构建一个这样的矩阵:
Transcript Id Gene Id(name) Mirna Name miTG score UTR3 MRE_score
ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1 21:30717414-30717442 0.13591267 我想在我的新矩阵中添加三个新列,分别是UTR3、MRE_score和CDS。
对于每个Gene ID (例如ENST00000286800),原始矩阵中有几个UTR3 (此处两个UTR3用于ENST00000286800,一个UTR3用于ENST00000345080)我们在第三列中选择得分最高的UTR3。在新矩阵中,每个Gene ID的UTR3的值将是原始矩阵第二列中的UTR3的值。
有没有人可以帮助我重塑这些数据并构建我的新矩阵?
发布于 2014-01-20 08:05:05
您可以尝试使用正则表达式来构造CSV:
textfile <- "ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1
UTR3 21:30717114-30717142 0.05994568
UTR3 21:30717414-30717442 0.13591267
ENST00000345080 ENSG00000187772 (LIN28B) hsa-let-7a-5p 1
UTR3 6:105526681-105526709 0.133514751"
txt <- readLines(textConnection(textfile))
sepr <- grepl("^ENST.*", txt)
r <- rle(sepr)
r <- r$lengths[!r$values]
regex <- "(\\S+)\\s+(\\S+)\\s(\\([^)]+\\)\\s+\\S+)\\s+(\\d+)"
m <- regexec(regex, txt[sepr])
m1 <- as.data.frame(t(sapply(regmatches(txt[sepr], m), "[", 2:5)))
m1 <- m1[rep(1:nrow(m1), r),]
regex <- "(\\S+)\\s+(\\S+)\\s+(\\S+)"
m <- regexec(regex, txt[!sepr])
m2 <- as.data.frame(t(sapply(regmatches(txt[!sepr], m), "[", 2:4)))
df <- cbind(m1, m2[,-1])
names(df) <- c("Transcript Id", "Gene Id(name)", "Mirna Name", "miTG score", "UTR3", "MRE_score" )
rownames(df) <- NULL
df
# Transcript Id Gene Id(name) Mirna Name miTG score UTR3 MRE_score
# 1 ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1 21:30717114-30717142 0.05994568
# 2 ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1 21:30717414-30717442 0.13591267
# 3 ENST00000345080 ENSG00000187772 (LIN28B) hsa-let-7a-5p 1 6:105526681-105526709 0.133514751发布于 2014-01-20 13:22:34
使用以下测试数据:
Lines <- " Transcript Id Gene Id(name) Mirna Name miTG score
ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1
UTR3 21:30717114-30717142 0.05994568
UTR3 21:30717414-30717442 0.13591267
ENST00000345080 ENSG00000187772 (LIN28B) hsa-let-7a-5p 1
UTR3 6:105526681-105526709 0.133514751"读取所有内容,并设置输出的名称和nms。然后使用累积和计算分组向量cs。非重复项是每个组的第一行,重复项是随后的行。按组合并这两组行,并提取出每组中最高的MRE_score:
DF <- read.table(text = Lines, header = TRUE, fill = TRUE, as.is = TRUE,
check.names = FALSE)
nms <- c("cs", names(DF)[1:5], "UTR3", "MRE_score") # out will have these names
DF$cs <- cumsum(!is.na(DF$Mirna)) # groups each ENST row with its UTR3 rows
dup <- duplicated(DF$cs) # FALSE for ENST rows and TRUE for UTR3 rows
both <- merge(DF[!dup, ], DF[dup, ], by = "cs")[c(1:6, 11:12)] # merge ENST & UTR3 rows
names(both) <- nms
both$MRE_score <- as.numeric(both$MRE_score)
Rank <- function(x) rank(x, ties.method = "first")
out <- both[ave(-both$MRE_score, both$cs, FUN = Rank) == 1, -1] # only keep largest score这是我们得到的:
> out
Transcript Id Gene Id(name) Mirna UTR3 MRE_score
2 ENST00000286800 ENSG00000156273 (BACH1) hsa-let-7a-5p 1 21:30717414-30717442 0.1359127
3 ENST00000345080 ENSG00000187772 (LIN28B) hsa-let-7a-5p 1 6:105526681-105526709 0.1335148请注意,该问题引用了一个CDS列,但它是什么没有描述,也没有出现在示例输出中,所以我们忽略了它。
https://stackoverflow.com/questions/21224026
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