proc format; 1-2='Lib or Extr Lib' 6-7='Cons or Extr Cons';我想要创建一个饼图,如果可能的话,可以考虑到我对这些连续值的分组,而不必修改数据本身。percent=arrow slice=inside value=inside coutline=black format ideol
我有条形图和下面的代码:
var line1=[['0-1',275134],['2-3',261562],['4-5',285681],['6-7',915432],['8-9',555131]];var line2=[['0-1',353628],['2-3',287898],['4-5',297550],['6-7',103313],['8-9&