,使得这两个字符串的长度乘积最大,输出这个最大的乘积。...找不到满足要求的两个字符串,则输出0
输入描述:
Input:
["a","ab","abc","cd","bcd","abcd"]
输出描述:
Output:
4
输入样例1:
["a","ab"...,"abc","cd","bcd","abcd"]
输出样例1:
4
说明:
Input中,不包含相同字符的有两对
"ab"和"cd"
"a"和"bcd"
所以字符串长度乘积的最大值是4
解题思路...自定义函数fun用于判断俩个字符串中有无重复字符,若有重复字符则返回0,否则返回这俩个字符串的长度乘积,这部分我是用set来实现的。...,若有重复字符则返回0,否则返回这俩个字符串的长度乘积
{
set s;
for(auto it : s1)
{
if(s.count(it) ==