Linux While loop/ If语句查询

Question

我有一个脚本，尽管我尽了最大的努力，但我还是不能去工作。我真的希望有人能帮上忙。对编程非常陌生，所以还在学习诀窍。我正在构建一个交互式shell脚本，它要求用户输入一个操作数，然后再放入另一个操作数，以生成第二个操作数的数学表。例如，我选择"+“&数字"2”(从15的范围)，它会打印出"2+1=3，2+2 =4“等的表格，范围是10。这是我当前的脚本；

#!/bin/sh
echo "Please select the function you wish to perform from the following list"
echo " Multiplication = *"
echo " Addition = +"
echo " Subtraction = -"
echo " Division = /"
echo " Exponent = ^"

read s

echo "Please select a number between 1 and 15"
read n
i = 1
while [$i ‽ le 10]
do
if [$s = "*"]
then
        echo "$n x $i = $((n*i))";

elif [ $s = "+"]
        echo "$n + $i = $((n+i))";
elif [$s = "-"]
        echo "$n - $i = $((n-i))";
elif [$s = "/"]
        echo "$n / $i = $((n/i))";
elif [$s = "^"]
        echo "$n ^ $i = $((n^i))";
fi
i = $((i+1))
done

我知道我的while循环是不正确的，所以我非常感谢大家的帮助！谢谢!

Answer 1

经过一些修改后：

    #!/bin/sh
    echo "Please select the function you wish to perform from the following list"
    echo " Multiplication = *"
    echo " Addition = +"
    echo " Subtraction = -"
    echo " Division = /"
    echo " Exponent = ^"

    read s
    echo "Please select a number between 1 and 15"
    read n
    i=1
    while [ "$i" -le 10 ] 
    do
    if [ "$s" = "*" ]; then
        echo "$n x $i = $((n*i))";

    elif [ "$s" = "+" ]; then
            echo "$n + $i = $((n+i))";
    elif [ "$s" = "-" ]; then
            echo "$n - $i = $((n-i))";
    elif [ "$s" = "/" ]; then
            echo "$n / $i = $((n/i))";
    elif [ "$s" = "^" ]; then
            echo "$n ^ $i = $((n^i))";
    fi
    i=$((i+1))
    done