Javers按顺序比较列表

Question

我有两个类似的java类：

public class FooA {
  private List<FooB> fooB;
}

public class FooB {
  private Integer id;
  private String name;
  private double num;
}

我想比较一下FooA，它会告诉我list对象中的哪些字段发生了变化。但是当我这样做的时候：

FooA old = new FooA(Arrays.asList(new FooB(1, "old", 1.0)));
FooA new = new FooA(Arrays.asList(new FooB(1, "new", 1.0)));

Javers javers = JaversBuilder.javers()
          .withListCompareAlgorithm(LEVENSHTEIN_DISTANCE)
          .build();

javers.compare(old, new);

它给了我这样的不同：

Diff:
* new object: com.FooA/#fooB/1d32d18fcb3ba2f7f7cb41af6cd96b32
* object removed: com.FooA/#fooB/223ef3c3249fe2898ac3354f9bf42620
* changes on com.FooA/ :
  - 'fooB' collection changes :
    . 'com.FooA/#fooB/223ef3c3249fe2898ac3354f9bf42620' removed
    . 'com.FooA/#fooB/1d32d18fcb3ba2f7f7cb41af6cd96b32' added

我甚至试着在FooB上添加一个Id，就像我在很多帖子中看到的那样。所以现在我的foob看起来像这样：

public class FooB {
  @Id
  private Integer id;
  private String name;
  private double num;
}

但现在，当我比较时，我得到了这个：

Diff:
* changes on com.FooB/1 :
  - 'name' changed from 'old' to 'new'

它注册为值更改，而不是集合更改。我希望diff读起来是这样的：

Diff:
* changes on com.FooA/#fooB/1 :
  - 'fooB' collection changes :
    . 'name' changed from 'old' to 'new'

我做错了什么？

Answer 1

使用Javers版本5.2.4

public class FooA {
    private List<FooB> fooB;

    public FooA(List<FooB> fooB) {
        this.fooB = fooB;
    }
}

public class FooB {
    private Integer id;
    private String name;
    private double num;

    public FooB(Integer id, String name, double num) {
        this.id = id;
        this.name = name;
        this.num = num;
    }
}

void test() {
    FooA old = new FooA(Arrays.asList(new FooB(1, "old", 1.0)));
    FooA new1 = new FooA(Arrays.asList(new FooB(1, "new", 1.0)));

    Javers javers = JaversBuilder.javers()
            .withListCompareAlgorithm(LEVENSHTEIN_DISTANCE)
            .build();

    System.out.println(
            javers.compare(old, new1)
    );
}

方法test返回：

Diff:
* changes on pl.javers.JaversTest$FooA/ :
  - 'fooB/0.name' changed from 'old' to 'new'

它几乎和你想要的一样。

FooA/fooB/0.name -> fooA具有数组fooB，并且first (索引0)名称属性已更改