我正在用amp-form做后端数据输入验证,我想在前端显示错误。然而,当我提交表单时,即使表单包含错误(没有输入姓名),前端也会说“成功!”而不是输出错误。
PHP代码:https://gist.github.com/Stefany93/364db9e088b570fff83387494e8459a4#file-php
action-xhr="scripts/contact_process.php"
verify-xhr="/scripts/contact_process.php"
method="post"
target="_blank"
class="detailed_contact_form "
custom-validation-reporting="as-you-go"
>
<fieldset class="user-valid valid">
<legend>
<span> Schedule an appointment</span>
</legend>
<div class="form-body">
<div class="form-group">
<div class="form-group">
<div class="form-group">
<label for="email">Email </label>
<input type="text" required name="email" id="email" value="exampleexample.com"class="form-input string-entry">
</div>
<label for="name">Name </label>
<input type="text" required name="name" id="name" value="Cindy" class="form-input string-entry">
</div>
<div class="form-group">
<label for="phone">Phone </label>
<input type="tel" required name="phone" id="phone" value="123-345-6789" class="form-input string-entry">
</div>
<div class="form-group">
<label for="phone">Message </label>
<textarea name="message" required class="textarea" >I want to schedule an appointment for my dragon Skippy, for tomorrow 10AM</textarea>
</div>
<div class="form-group button-holder">
<input type="submit" class="button" value="Send appointment!">
</div>
</div>
<div verify-error>
<template type="amp-mustache">
{{#verifyErrors}}
<p>{{message}}</p>
{{/verifyErrors}}
{{^verifyErrors}}
<p>Something went wrong. Try again later?</p>
{{/verifyErrors}}
</template>
</div>
<div submit-error>
<template type="amp-mustache">
{{#verifyErrors}}
<p>{{message}}</p>
{{/verifyErrors}}
{{^verifyErrors}}
<p>Something went wrong. Try again later?</p>
{{/verifyErrors}}
</template>
</div>
<div submit-success>
<template type="amp-mustache">
Success!
</template>
</div>
</fieldset>
</form> ```发布于 2019-06-08 06:10:12
我收到了一条成功的消息,因为AMP跟踪HTTP头,每当我提交表单时,如果提交成功(即使我因为错误而无法发送电子邮件),contact_process.php会返回一个HTTP头2xx,然后AMP会认为它是成功的。
submit-success将在成功提交表单时输出,无论表单是否执行了您希望它做的事情。
只要后端返回4xxx的HTTP头,submit-error就会输出。在我的例子中,我必须添加下面这行代码:
header("HTTP/1.1 400 Bad Request");
在echo json_encode($error_array)下面,它起作用了!
每当您想输出错误时,请确保手动发送错误HTTP头4xx。
https://stackoverflow.com/questions/56419038
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