在Hound中单击一次后，如何断言元素存在？

Question

我使用Hound作为webdriver框架来利用Elixir中的Selenium。我在测试facebook账号的创建。在我填写了否定测试(firstname = Roberto，lastname =asdlkfj；)之后，我单击了submit，我试图得到一个错误，因为我没有正确的姓氏。问题是Hound没有等待元素被显示，并返回了一个元素未找到错误。我该如何处理这个问题，并让测试等待元素加载呢？下面是我的代码：

  test "Last name with random characters" do
    counter = :rand.uniform(100)
    navigate_to "https://www.facebook.com"
    first_name = find_element(:name, "firstname")
    fill_field(first_name, "Jorge")
    last_name = find_element(:name, "lastname")
    fill_field(last_name, "asdfja;lsdf")
    email_input = "robbie#{counter}@gmail.com"
    email = find_element(:name, "reg_email__")
    fill_field(email, email_input)
    confirm_email = find_element(:name, "reg_email_confirmation__")
    fill_field(confirm_email, email_input)
    password_input = "123456Test"
    password = find_element(:name, "reg_passwd__")
    fill_field(password, password_input)
    #Birthday
    birth_month = find_element(:css, "#month > option:nth-child(5)")
    birth_day = find_element(:css, "#day > option:nth-child(25)")
    birth_year = find_element(:css, "#year > option:nth-child(22)")
    click(birth_month)
    click(birth_day)
    click(birth_year)
    #gender
    select_gender = find_element(:css, "#u_0_s > span:nth-child(2)")
    click(select_gender)
    sign_up_button = find_element(:name, "websubmit")
    click(sign_up_button)

    search = find_element(:id, "#reg_error_inner")
    # found = element_displayed?("#reg_error_inner")
    IO.puts(search)
    # assert found == true
    # :timer.sleep(10000)
   end```

Answer 1

使用search_element而不是find_element。如果成功，search_element将返回{:ok, element}，如果失败，将返回{:error, error}。如果您只想断言元素存在，那么您可以：

assert {:ok, _} = search_element(:id, "#reg_error_inner")

如果您还希望将其放在变量中以进行进一步处理，则：

assert {:ok, element} = search_element(:id, "#reg_error_inner")

如果要将其转换为布尔值，则：

match?({:ok, _}, search_element(:id, "#reg_error_inner"))