从异步函数获取promise来自非异步函数

Question

所以我的问题是，当我验证用户凭证时，来自login()的承诺还没有被解决。因此loginResult将是Promise{}。我知道我需要等待一些结果，但无论如何我都能想到。

任何建议都很感谢。这是为了一个学校的项目，所以请不要责备我，这是多么不安全。

var express = require('express');
var router = express.Router();
var login = require('../controller/authenticate/login');

/* GET users listing. */
router.get('/', function (req, res, next) {
  res.send('respond with a resource');
});

/* Login user */
router.post('/login', function (req, res, next) {
  const username = req.body.username;

  // This is a async return so its not working right. Currently only reading Promise{<pending>}
  let loginResult = login(username, req.body.password);

  console.log(loginResult)
  if (loginResult === true) {
    res.render('users', {username: username});
  }
  else {
    res.render('index', {error: true});
  }
});

module.exports = router;

Answer 1

是像这样吗？

在函数前面添加async，然后添加await

router.post('/login', async function (req, res, next) {
  const username = req.body.username;

  const loginResult = await login(username, req.body.password);

  console.log(loginResult)

  if (loginResult === true) {
    res.render('users', {username: username});
  } else {
    res.render('index', {error: true});
  }
});

或者使用Promises和then

router.post('/login', function (req, res, next) {
  const username = req.body.username;

  login(username, req.body.password)
    .then(resp => {
      console.log(resp)
      if (resp === true) {
        res.render('users', {username: username});
      } else {
        res.render('index', {error: true});
      }
    });
});