比较两个数组和JSON对象作为python中的项的最佳方法

Question

您有两个数组(虚拟值)，数组中的每个项目都包含JSON对象：

ArrayOne：

[{'keyboards': '1'}, {'keyboards': '2'}, {'keyboards': '3'}, {'mice': '1'}]

ArrayTwo：

[{'keyboards': '1'}, {'keyboards': '2'}, {'mice': '1'}]

我希望同时遍历每个数组，如果arrayOne中的值在arrayTwo中存在，但在arrayTwo中不存在，则将其标记出来(做点什么)。

这是我的代码示例：

for deviceAndID in ArrayOne:
        if deviceAndID in ArrayTwo:
             print("It exists in both arrays")
        else:
             print("Device " + str(deviceAndID) + "is not in arrayTwo")

在此代码示例中，它为最大数组中的每个值输出(示例) Device {'keyboard': '1'} is not in arrayTwo。

实际上，我需要它根据上面的两个数组打印出以下内容：

It exists in both arrays
It exists in both arrays
Device {'keyboard': '3'} is not in arrayTwo
It exists in both arrays

我感觉这个问题是由每个元素或项目都是一个json对象引起的，那么考虑到它们是列表中的JSON对象，我该如何处理呢？

Answer 1

这是我根据你的问题得到的：

>>> ArrayOne = [{'keyboards': '1'}, {'keyboards': '2'}, {'keyboards': '3'}, {'mice': '1'}]
>>> ArrayTwo = [{'keyboards': '1'}, {'keyboards': '2'}, {'mice': '1'}]
>>> for deviceAndID in ArrayOne:
        if deviceAndID in ArrayTwo:
             print("It exists in both arrays")
        else:
             print("Device " + str(deviceAndID) + "is not in arrayTwo")

             
It exists in both arrays
It exists in both arrays
Device {'keyboards': '3'}is not in arrayTwo
It exists in both arrays