我正在创建一个简单的Java8 concurrency CountDownLatch示例。我正在创建一个大小为2的闩锁,并启动2个线程,并在闩锁上调用await。请参见下面的示例。
package CountDownLatchExample;
import java.util.concurrent.CountDownLatch;
public class CountDownLatchExample {
static final CountDownLatch latch = new CountDownLatch(2);
public static void main(String[] args) throws InterruptedException {
MyThread thread = new MyThread(latch);
new Thread(thread).start();
new Thread(thread).start();
latch.await();
System.out.println(Thread.currentThread().getName() + " done.");
}
}
class MyThread implements Runnable {
CountDownLatch latch;
MyThread(CountDownLatch latch) {
this.latch = latch;
}
@Override
public void run() {
latch.countDown();
System.out.println(Thread.currentThread().getName() + " completed.");
}
}我期望Thread-0,Thread-1在main完成之前完成(基于sysout)。然而,当我执行程序时,有时甚至在Thread-1完成之前就会打印出"main done“消息。是我的实现或我的理解不正确吗?请提个建议。
输出:
> Task :CountDownLatchExample.main()
Thread-0 completed.
main done.
Thread-1 completed.发布于 2020-01-29 13:39:07
当我执行的时候,我得到了这个输出:
Thread-0 completed.
Thread-1 completed.
main done.线程之间的上下文切换也可以在run方法中调用latch.countDown();之后发生。我建议您修改run方法,如下所示,以获得理想和一致的结果。
@Override
public void run() {
System.out.println(Thread.currentThread().getName() + " completed.");
latch.countDown();
}https://stackoverflow.com/questions/59960435
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