我已经下载了iPhone版和iOS版的Windows8黄金版。
我测试了这个应用程序,它运行良好,除了一件事。
我有一个文本字段,如果用户想要键入什么,就会出现一个数字键盘,此外,当键盘出现时,会在空白区域添加一个自定义按钮。
- (void)addButtonToKeyboard
{
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
// create custom button
UIButton * doneButton = [UIButton buttonWithType:UIButtonTypeCustom];
doneButton.frame = CGRectMake(-2, 163, 106, 53);
doneButton.adjustsImageWhenHighlighted = NO;
[doneButton setImage:[UIImage imageNamed:@"DoneUp.png"] forState:UIControlStateNormal];
[doneButton setImage:[UIImage imageNamed:@"DoneDown.png"] forState:UIControlStateHighlighted];
[doneButton addTarget:self action:@selector(saveNewLead:) forControlEvents:UIControlEventTouchUpInside];
// locate keyboard view
UIWindow * tempWindow = [[[UIApplication sharedApplication] windows]objectAtIndex:1];
UIView* keyboard;
for(int i=0; i<[tempWindow.subviews count]; i++)
{
keyboard = [tempWindow.subviews objectAtIndex:i];
// keyboard view found; add the custom button to it
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 3.2) {
if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES)
[keyboard addSubview:doneButton];
} else {
if([[keyboard description] hasPrefix:@"<UIKeyboard"] == YES)
[keyboard addSubview:doneButton];
}
}
}
}到目前为止,这个方法运行得很好。
首先,我得到这样的警告:
找不到支持类型4的键盘iPhone-肖像-数字键盘;使用3876877096_肖像_iPhone-简单键盘-默认键盘
那么自定义按钮也不会显示,我认为这是因为这两行代码:
if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES)和
if([[keyboard description] hasPrefix:@"<UIKeyboard"] == YES)有什么建议吗?
发布于 2014-09-22 17:45:44
我也遇到了这个问题,并找到了解决方案。
下面是适用于iOS 8.0和以下版本的代码。
我已经在iOS 7和8.0 (Xcode6.0.1版)上进行了测试。
- (void)addButtonToKeyboard
{
// create custom button
self.doneButton = [UIButton buttonWithType:UIButtonTypeCustom];
//This code will work on iOS 8.3 and 8.4.
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.3) {
self.doneButton.frame = CGRectMake(0, [[UIScreen mainScreen] bounds].size.height - 53, 106, 53);
} else {
self.doneButton.frame = CGRectMake(0, 163+44, 106, 53);
}
self.doneButton.adjustsImageWhenHighlighted = NO;
[self.doneButton setTag:67123];
[self.doneButton setImage:[UIImage imageNamed:@"doneup1.png"] forState:UIControlStateNormal];
[self.doneButton setImage:[UIImage imageNamed:@"donedown1.png"] forState:UIControlStateHighlighted];
[self.doneButton addTarget:self action:@selector(doneButton:) forControlEvents:UIControlEventTouchUpInside];
// locate keyboard view
int windowCount = [[[UIApplication sharedApplication] windows] count];
if (windowCount < 2) {
return;
}
UIWindow *tempWindow = [[[UIApplication sharedApplication] windows] objectAtIndex:1];
UIView *keyboard;
for (int i = 0; i < [tempWindow.subviews count]; i++) {
keyboard = [tempWindow.subviews objectAtIndex:i];
// keyboard found, add the button
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.3) {
UIButton *searchbtn = (UIButton *)[keyboard viewWithTag:67123];
if (searchbtn == nil)
[keyboard addSubview:self.doneButton];
} else {
if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES) {
UIButton *searchbtn = (UIButton *)[keyboard viewWithTag:67123];
if (searchbtn == nil)//to avoid adding again and again as per my requirement (previous and next button on keyboard)
[keyboard addSubview:self.doneButton];
} //This code will work on iOS 8.0
else if([[keyboard description] hasPrefix:@"<UIInputSetContainerView"] == YES) {
for (int i = 0; i < [keyboard.subviews count]; i++)
{
UIView *hostkeyboard = [keyboard.subviews objectAtIndex:i];
if([[hostkeyboard description] hasPrefix:@"<UIInputSetHost"] == YES) {
UIButton *donebtn = (UIButton *)[hostkeyboard viewWithTag:67123];
if (donebtn == nil)//to avoid adding again and again as per my requirement (previous and next button on keyboard)
[hostkeyboard addSubview:self.doneButton];
}
}
}
}
}
}- (void)removedSearchButtonFromKeypad
{
int windowCount = [[[UIApplication sharedApplication] windows] count];
if (windowCount < 2) {
return;
}
UIWindow *tempWindow = [[[UIApplication sharedApplication] windows] objectAtIndex:1];
for (int i = 0 ; i < [tempWindow.subviews count] ; i++)
{
UIView *keyboard = [tempWindow.subviews objectAtIndex:i];
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.3){
[self removeButton:keyboard];
} else if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES) {
[self removeButton:keyboard];
} else if([[keyboard description] hasPrefix:@"<UIInputSetContainerView"] == YES){
for (int i = 0 ; i < [keyboard.subviews count] ; i++)
{
UIView *hostkeyboard = [keyboard.subviews objectAtIndex:i];
if([[hostkeyboard description] hasPrefix:@"<UIInputSetHost"] == YES) {
[self removeButton:hostkeyboard];
}
}
}
}
}
- (void)removeButton:(UIView *)keypadView
{
UIButton *donebtn = (UIButton *)[keypadView viewWithTag:67123];
if(donebtn) {
[donebtn removeFromSuperview];
donebtn = nil;
}
}希望这能有所帮助。
但是,我仍然收到这样的警告:
找不到支持类型4的键盘iPhone-肖像-数字键盘;使用3876877096_肖像_iPhone-简单键盘-默认键盘
忽略这个警告,我让它正常工作。如果你能从这个警告中得到缓解,请让我知道。
发布于 2014-09-21 06:54:27
在更新到最新的Xcode测试版后,我也遇到了这个问题。模拟器上的设置已刷新,因此检测到笔记本电脑(外部)键盘。如果您只需按:
iOS模拟器->硬件->键盘->连接硬件键盘
因此该条目为UNchecked,则软键盘将再次显示。
发布于 2015-11-22 10:01:17
模拟器试图在苹果电脑上找到一个数字键盘,但没有找到(MacBook Pro,MacBook Air和"normal/small“键盘没有)。您可以取消选择Connect Hardware Keyboard选项或忽略该错误消息,它不会对应用程序产生负面影响。
https://stackoverflow.com/questions/25842168
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