是否可以将两个函数的返回值相减？

Question

这里是api的wiki：https://github.com/ppy/osu-api/wiki

所以我构建了这个程序来比较排名，所以我抓取了用户名和他们的排名，现在我被困在如何存储信息上，然后用两者相减来得出差值！

抱歉，我只写了2-4周的代码，我确信这是非常简单的事情，我的代码可能非常恶心。

我目前拥有的代码如下：

def player1():
    payload = {'k': 'myapi', 'u': input()}
    r = requests.get('https://osu.ppy.sh/api/get_user', params=payload)

    player = r.json()[0]
    return (player["pp_country_rank"])
player = player1()
print(player)

print('Enter a second Username')

def player2():
    payload = {'k': 'myapi', 'u': input()}
    r = requests.get('https://osu.ppy.sh/api/get_user', params=payload)

    player = r.json()[0]
    return (player["pp_country_rank"])
player = player2()
print(player)

Answer 1

当你调用一个函数并返回结果时，你可以将它保存到一个新的变量中以供以后使用：

newVar = function()

这意味着在稍后的代码中，您可以将其用于其他用途。此外，当您创建一个函数时，您可以定义在函数中使用的变量，这些变量可以在调用函数时传递。对于您的示例，您可能希望传递"username“变量，而不是在有效负载中进行输入。

def myFunc(username):
    print(username)
myFunc(random_user)

由于我无法访问您的API，因此我创建了一个修改后的示例，并在下面添加了注释，该示例应该以与您得到的返回类似的方式进行操作。如果您从API服务器上发布了一个JSON示例，那么就会更容易有一个可运行的示例。

# Temp DB Dictionary for showing how things work
users = {
    "user1": [
        {
            "pp_country_rank": 100,
            "other_data": "random"
        }
    ],
    "user2": [
        {
            "pp_country_rank": 95,
            "other_data": "more-random"
        }
    ],
}

# Defining the function. This can be used over and over.
# In this case there will be a variable created in the
# function called "username". If this isn't passed to the
# function when you call it then it will be set to user1.
# If you do set it, whatever you set it to when you call
# the function will overwrite the default.
def getRank(username="user1"):
    # payload = {'k': 'myapi', 'u': username}
    # r = requests.get('https://osu.ppy.sh/api/get_user', params=payload)
    # Since we created the username variable I can past
    # it to whatever I am calling.
    r = users[username]
    #player = r.json()[0]
    player = r[0]
    # The return here returns the result that gets stored in
    # the variable.
    return (player["pp_country_rank"])

print("Enter first username")
# We are calling the input before passing the result to the
# function
user1 = input()
# We are creating a new variable that will store the result of
# the function getRank(). We pass the stored input of user1 to
# the functuon. In the function that data will be available as
# the variable "username"
user1_rank = getRank(user1)
# There are different ways of formatting and using variables in
# the print. This is one way and where the %s is it will be 
# replaced in order with the variables at the end.
print("%s rank is %s" % (user1, user1_rank))
# We get the second username again storing the input in user2
print('Enter a second Username')
user2 = input()
# We call the same function getRank() but this time we pass the
# data from user2 instead of user1.
user2_rank = getRank(user2)
print("%s rank is %s" % (user2, user2_rank))

# Here we are doing the diff between the two ranks. If you do not
# use abs() then you would have to figure out which rank was bigger
# before doing the substraction to avoid a negative number. This 
# way you will also have a positive diff.
rankDiff = abs(user1_rank - user2_rank)
print("The difference in ranks is %s" % rankDiff)

Answer 2

感谢Aldric的帮助，Austin意识到我犯了一个错误...初学者的东西。

def player1():
    payload = {'k': '306369747588b5614d76e123cee49dde8f439f7b', 'u': input()}
    r = requests.get('https://osu.ppy.sh/api/get_user', params=payload)

    player_1 = r.json()[0]
    return int(player_1["pp_country_rank"])
player_1 = player1()
print(player_1)

print('Enter a second Username')

def player2():
    payload = {'k': '306369747588b5614d76e123cee49dde8f439f7b', 'u': input()}
    r = requests.get('https://osu.ppy.sh/api/get_user', params=payload)

    player = r.json()[0]
    return int(player["pp_country_rank"])
player = player2()
print(player)

print ('Your difference in rank is:')
output = (player_1 - player)
print (output) 

是我的代码现在的样子，我得到了一些小错误，比如当player_1比player高得多时，它会返回一个负整数，并清理代码，因为其中一些与我从奥斯汀获得的代码相比是毫无意义的，只要我可以将它们都放在同一个函数中。但至少--我把它变成了自己的目标！:)