在OpenTest中，我们如何使用formdata而不是json进行POST服务调用呢？

Question

我们有一个以formData键值对作为请求的WebService，而不是json。使用openTest，我们如何传递这些formData？基本上，我们需要一个代码片段来发布使用OpenTest yaml脚本的formData。

下面是示例curl命令，我们需要使用OpenTest进行post，它的Content-Type为multipart/form-data

`
curl --location --request POST 'https://serviceurl.com/getacb' \
--form 'userKey=a1b23' \
--form 'apiKey=1_ffER_hk6Rb89--2EElfsdeF3' \
--form 'secret=Ude+6NIjojo89/gyAB7huGS5' \
--form 'targetUID=ulknnk4kjlkj5'
`

我们正在寻找一个样本片段来发布上面的multipart/form-data。

Answer 1

您需要自己构建FormData()对象，然后才能将其传递给下一个操作。

var data = new FormData();
data.append("userKey", "a1b23");
data.append("apiKey", "1_ffER_hk6Rb89--2EElfsdeF3");
data.append("secret", "Ude+6NIjojo89/gyAB7huGS5");
data.append("targetUID", "ulknnk4kjlkj5");

这是来自OpenTest API testing YAML的一些修改后的示例。

description: Example Post based off SO Question
actors:
  - actor: ACTOR1
    segments:
      - segment: 1
        actions:
          - description: Create a random post ID
            script: | 
              var data = new FormData();
              data.append("userKey", "a1b23");
              data.append("apiKey", "1_ffER_hk6Rb89--2EElfsdeF3");
              data.append("secret", "Ude+6NIjojo89/gyAB7huGS5");
              data.append("targetUID", "ulknnk4kjlkj5");

          - description: Send a request to getacb
            action: org.getopentest.actions.HttpRequest
            args:
              url: https://serviceurl.com/getacb
              headers:
                Content-Type: multipart/form-data
              verb: POST
              body: data

          - description: Extract the response's status code and body
            script: |
              var statusCode = $output.statusCode;
              var postInfo = $output.body;

          - description: Validate the response status code
            script: |
              if (statusCode != 201) {
                $fail($format(
                  "We expected the status code to be {0} but it was {1}",
                  201,
                  statusCode));
              }