random.shuffle不会洗牌

Question

我正在构建一副具有洗牌功能的纸牌。我使用的是random.shuffle，但它根本不是随机的。当我运行以下代码时，整个打印板都打印得井井有条。请看一看，谢谢！

import random


class Card(object):
    def __init__(self, suit, value):
        self.suit = suit
        self.value = value

    def show(self):
        print("{} of {}".format(self.value, self.suit))
        return self.value


class Deck(object):
    def __init__(self):
        self.cards = []
        self.build()

    def build(self):
        for s in ["Spades", "Clubs", "Diamonds", "Hearts"]:
            for v in range(1, 14):
                self.cards.append(Card(s, v))
                print("{} of {}". format(v, s))

    def show(self):
        for cards in self.cards:
            print(cards.show())

    def shuffle(self):
        random.shuffle(self.cards)
        return self.cards

    def draw_card(self):
        return self.cards.pop()


deck = Deck()
deck.shuffle()

Answer 1

我刚刚测试了您的代码，您看到的顺序良好的控制台输出消息是从self.build()函数创建的，如果您在最后调用deck.show()，您将看到随机排列的消息。

deck = Deck()
deck.shuffle()
deck.show()