python -如何让函数检查按钮是否被按下一次或两次？

Question

我正在试着用Python为学校做一个任务。但问题是，我不明白以下功能是如何工作的:所以我们正在尝试制作一个带有灯和继电器的智能手机(现在我们使用LED)。如果我们按下按钮一次，灯就亮了，如果我们在1.5秒内按两次，所有的灯都亮了，以此类推……我们还必须在灯已经亮起的时候做一个函数……

因此，我的问题是“我如何告诉或让python知道我按了一次、两次或更多按钮，或者按住它，让它执行某个功能？”

这是我的代码(我们在空中上传到Raspberry Pi

#!/usr/bin/env

__author__ = "Zino Henderickx"
__version__ = "1.0"

# LIBRARIES
from gpiozero import LED
from gpiozero import Button
from gpiozero.pins.pigpio import PiGPIOFactory
import time

IP = PiGPIOFactory('192.168.0.207')

# LED's
LED1 = LED(17, pin_factory=IP)
LED2 = LED(27, pin_factory=IP)
LED3 = LED(22, pin_factory=IP)
LED4 = LED(10, pin_factory=IP)


# BUTTONS
BUTTON1 = Button(5, pin_factory=IP)
BUTTON2 = Button(6, pin_factory=IP)
BUTTON3 = Button(13, pin_factory=IP)
BUTTON4 = Button(19, pin_factory=IP)


# LISTS

led [10, 17, 22, 27]
button [5, 6, 13, 19]

def button_1():
    if BUTTON1.value == 1:
        LED1.on()
        time.sleep(0.50)
    if BUTTON1.value == 0:
        LED1.on()
        time.sleep(0.50)


def button_2():
    if BUTTON2.value == 1:
        LED2.on()
        time.sleep(0.50)
    if BUTTON2.value == 0:
        LED2.on()
        time.sleep(0.50)


def button_3():
    if BUTTON3.value == 1:
        LED3.on()
        time.sleep(0.50)
    if BUTTON3.value == 0:
        LED3.on()
        time.sleep(0.50)


def button_4():
    if BUTTON4.value == 1:
        LED4.on()
        time.sleep(0.50)
    if BUTTON4.value == 0:
        LED4.on()
        time.sleep(0.50)

def check_button():
    while True:
        for i in range(BUTTON1):
            toggle_button(i)


def main():
    set_up_led()
    set_up_button()
    check_button()

# MAIN START PROGRAM


if __name__ == "__main__":
    main()

Answer 1

你有没有想过设置一个只要按下按钮就会响的计时器？这将触发一个循环，该循环将在给定时间内检查按钮是否再次被按下。如果时间已过，则循环结束并执行一条指令，如果按钮已重置，则程序执行另一条指令。

import time
#define max_time to consider a double execution
max_time = 1
while 1:
    time.sleep(0.001) # do not use all the cpu power
    # make a loop to test for the button being pressed
    if button == pressed:
        when_pressed = time.time()
        while time.time() - when_pressed < max_time:
            time.sleep(0.001) # do not use all the cpu power
            if button == pressed:
                # Instructions 2
        #Instructions 1