无法执行赋值，因为左侧和右侧的元素数量不同。MATLAB错误

Question

我试着用MATLAB计算几个矩阵。运行这段代码后，我得到一个错误消息："Unable to perform assignment，因为左侧和右侧的元素数量不同。“经过简单的调试，我得到的结论是，在注释X(j)和Y(j)之后，程序运行正常。我看过一些类似的问题，但我找不到能帮助我解决上述问题的东西。

 clear all
close all
clc
%stale
a1 = 1;
a2 = 1;
a3 = 1;
a4 = 1;
a5 = 1;

%% Napęd 2
X=0; Y=0; Z=0;
th1 = 0; th2 = 0; th3 = 0; th4 = 0; th5 = 0;
%alfa2 = 1;
alfa2 = 0:(pi/12):(pi);
alfa1 = 0; alfa3 = 0; alfa4 = 0; alfa5 = 0;
d5=1; d4=1; d3=1; d2=1; d1=1;
a3 = 1;
a3 = 0.1:(1/14):1;
 
for j = 1 : length(alfa2)
    X(j) = a5*cos(th1)*cos(th4)*cos(th5) + a5*sin(th1)*sin(alfa2(j))*sin(th4)*cos(th5) - a5*cos(th1)*sin(th4)*sin(th5) + a5*sin(th1)*sin(alfa2(j))*cos(th4)*sin(th5) + d4*sin(th1)*cos(alfa2(j)) + a3*cos(th1) + alfa2*cos(th1);
 
    Y(j) = a5*sin(th1)*sin(th4)*cos(th5) - a5*cos(th1)*sin(alfa2(j))*cos(th4)*cos(th5) - a5*sin(th1)*sin(th4)*sin(th5) - a5*cos(th1)*sin(alfa2(j))*cos(th4)*sin(th5) + d4*sin(th1)*cos(alfa2(j)) + a3*cos(th1) + alfa2*cos(th1);
 
    Z(j) = a5*cos(alfa2(j))*sin(th4)*cos(th5) + a5*cos(alfa2(j))*cos(th4)*sin(th5) -d4*sin(alfa2(j)) + d1;
end
figure(1);
subplot(2, 2, 1); plot3(Y, X, Z); grid on; title("Przestrzen XYZ");
xlabel('y'); ylabel('X'); zlabel('Z')
subplot(2, 2, 2); plot(Y, X); grid on; xlabel('Y'); ylabel('X');
title("Plaszczyzna XY");
subplot(2, 2, 3); plot(X, Z); grid on; xlabel('X'); ylabel('Z');
title("Plaszczyzna XZ");
subplot(2, 2, 4); plot(Y, Z); grid on; xlabel('Y'); ylabel('Z');
title("Plaszczyzna YZ");

这是我的工作区：Workspace

Answer 1

您在方程式的末尾使用了alpha2，它是一个向量。您可能需要alpha2(j)