如何使我的代码更有效，更少耗时

Question

因此，下面是一段代码

#Check if inputs is empty, if they are, delete them
if(table_parameters['parameter1'] == " "):
  del table_parameter['parameter1']
if(table_parameters['parameter2'] == " "):
  del tatble_parameters['parameter2']
if(table_parameters['parameter3'] == " "):
  del table_parameters['parameter3']
if(table_parameters['parameter4'] == " "):
  del table_parameters['parameter4']

它检查table_parameters(字典)的一部分是否为空，如果是，则删除该变量。我如何才能使它更有效，而不必硬编码所有这些检查？我有时想将其扩展到9个可选(1个是必需的)，但我认为必须有某种方法才能不必硬编码20行代码来进行简单的检查。下面是我的代码库的更大部分

import sqlite3
db_name = input("Enter wanted name of database: ") + ".db"
table_name = input("Enter wanted name of table: ")

table_parameters = {
  "parameter1": input("enter 1.st here: "),
  "parameter2": input("enter 2.nd here: "),
  "parameter3": input("Enter 3rd: "),
  "parameter4": input("Enter 3rd: "),
  "parameter5": input("Enter 3rd: "),
  "parameter6": input("Enter 3rd: "),
  "parameter7": input("Enter 3rd: "),
  "parameter8": input("Enter 3rd: "),
  "parameter9": input("Enter 3rd: "),
  "parameter10": input("Enter 3rd: "),

}

#Check if inputs is empty, if they are, delete them
if(table_parameters['parameter1'] == " "):
  del table_parameter['parameter1']
if(table_parameters['parameter2'] == " "):
  del tatble_parameters['parameter2']
if(table_parameters['parameter3'] == " "):
  del table_parameters['parameter3']
if(table_parameters['parameter4'] == " "):
  del table_parameters['parameter4']


conn = sqlite3.connect(f"{db_name}")

Answer 1

通过对所有值进行迭代或使用字典解释来创建一个新的口述。

>>> table_parameters = {1:10, 2:None, 3:30, 4: ' '}
>>> table_parameters = {x:y for x,y in table_parameters.items() if y is not None and y != ' '}
>>> table_parameters
{1: 10, 3: 30}
>>> 

Answer 2

一个可能的选项是，例如，首先定义什么是空的

empty_values = ["", " ", None]

然后，您可以根据以下可能的空值列表检查您的dict的值：

for key, value in table_parameters.keys():
    if value in empty_values:
        del table_parameters[key]

编辑:根据Reti43增加.keys()