如何在bicep模板中定义基于身份的数据访问

Question

我有以下作为二头肌模板，我想使用基于身份的连接，我如何才能建立相应的模板。

https://docs.microsoft.com/en-us/azure/azure-functions/functions-reference#connecting-to-host-storage-with-an-identity

我在这里使用了https://docs.microsoft.com/en-us/azure/azure-resource-manager/bicep/quickstart-create-bicep-use-visual-studio-code?tabs=PowerShell的指导来进行部署。

New-AzResourceGroup -Name exampleRG -Location eastus

New-AzResourceGroupDeployment -ResourceGroupName exampleRG -TemplateFile ./main.bicep -storageName "{your-unique-name}" 

但是，我在处理模板文件时遇到错误- Code=InvalidTemplateDeployment；根据验证过程，Message=The模板部署'bicepeg‘无效

var baseName = uniqueString('identityRepro', subscription().id)
var location = 'uksouth'

resource stg 'Microsoft.Storage/storageAccounts@2019-06-01' = {
  name: baseName
  location: location 
  sku: {
    name: 'Standard_LRS'
  }
  kind: 'StorageV2'
}

resource asp 'Microsoft.Web/serverfarms@2019-08-01' = {
  name: baseName
  location: location
  sku: {
    name: 'Y1'
    tier: 'Dynamic'
  }
}

resource ai 'Microsoft.Insights/components@2015-05-01' = {
  name: baseName
  location: location
  kind: 'web'
  properties: {
    Application_Type: 'web'
  }
}

resource fa 'Microsoft.Web/sites@2019-08-01' = {
  name: baseName
  location: location
  identity: {
    type: 'SystemAssigned'
  }
  properties: {
    serverFarmId: asp.id
  }
  kind: 'functionapp'

  resource appSettings 'config@2018-11-01' = {
    name: 'appsettings'
    properties: {
      'AzureWebJobsStorage__accountName': stg.name
      'FUNCTIONS_WORKER_RUNTIME': 'powershell'
      'FUNCTIONS_WORKER_RUNTIME_VERSION': '~7'
      'APPINSIGHTS_INSTRUMENTATIONKEY': ai.properties.InstrumentationKey
    }
  }
}

resource blobContrib 'Microsoft.Authorization/roleAssignments@2020-04-01-preview' = {
  name: guid(fa.name, stg.name, 'ba92f.........d-a403-e96b0029c9fe')
  properties: {
    principalId: fa.identity.principalId
    roleDefinitionId: resourceId('Microsoft.Authorization/roleDefinitions', 'ba92f.......-a403-e96b0029c9fe')
    principalType: 'ServicePrincipal'
  }
  scope: stg
}

Answer 1

我认为你的问题在于角色的身份。角色在订阅级别定义，而不是在资源组中定义。在您代码中，使用subscriptionResourceId代替resourceId函数。

更新:随着您对github问题的更多澄清，您的附加问题是名称是如何构造的。uniqueString函数根据种子(您提供给函数的参数)生成伪随机字符串(散列)。当你给出完全相同的值时，你会得到同样的结果。

下面的代码对我很有效

var baseName = uniqueString(resourceGroup().id)
var location = 'uksouth'

resource stg 'Microsoft.Storage/storageAccounts@2019-06-01' = {
  name: baseName
  location: location 
  sku: {
    name: 'Standard_LRS'
  }
  kind: 'StorageV2'
}

resource asp 'Microsoft.Web/serverfarms@2019-08-01' = {
  name: baseName
  location: location
  sku: {
    name: 'Y1'
    tier: 'Dynamic'
  }
}

resource ai 'Microsoft.Insights/components@2015-05-01' = {
  name: baseName
  location: location
  kind: 'web'
  properties: {
    Application_Type: 'web'
  }
}

resource fa 'Microsoft.Web/sites@2019-08-01' = {
  name: baseName
  location: location
  identity: {
    type: 'SystemAssigned'
  }
  properties: {
    serverFarmId: asp.id
  }
  kind: 'functionapp'

  resource appSettings 'config@2018-11-01' = {
    name: 'appsettings'
    properties: {
      'AzureWebJobsStorage__accountName': stg.name
      'FUNCTIONS_WORKER_RUNTIME': 'powershell'
      'FUNCTIONS_WORKER_RUNTIME_VERSION': '~7'
      'APPINSIGHTS_INSTRUMENTATIONKEY': ai.properties.InstrumentationKey
    }
  }
}

resource blobContrib 'Microsoft.Authorization/roleAssignments@2020-04-01-preview' = {
  name: guid(fa.name, stg.name, 'ba92f5b4-2d11-453d-a403-e96b0029c9fe')
  properties: {
    principalId: fa.identity.principalId
    roleDefinitionId: subscriptionResourceId('Microsoft.Authorization/roleDefinitions', 'ba92f5b4-2d11-453d-a403-e96b0029c9fe')
    principalType: 'ServicePrincipal'
  }
  scope: stg
}

在您的代码中使用resourceGroup().id作为uniqueString参数-因为它包含您的订阅的唯一guid和资源组名称(在订阅中必须是唯一的)-您的散列也应该是唯一的。仅提供subscription().id将为其中该订阅和资源组的所有部署生成相同的字符串。