fun main() {
Single.just("faefw")
.subscribeOn(Schedulers.trampoline())
.map {
println("map in thread ${Thread.currentThread().name}")
}
.flatMap {
return@flatMap Single.just(231).map {
println("map in thread ${Thread.currentThread().name}")
return@map it
}
}
.subscribe({
println(it)
}, {
println(it)
})
}打印输出:
map in thread main
map in thread main
231但
fun main() {
Single.just("faefw")
.subscribeOn(Schedulers.io())
.map {
println("map in thread ${Thread.currentThread().name}")
}
.flatMap {
return@flatMap Single.just(231).map {
println("map in thread ${Thread.currentThread().name}")
return@map it
}
}
.subscribe({
println(it)
}, {
println(it)
})
}不输出任何内容!
subscribeOn(Schedulers.computation())和subscribeOn(Schedulers.newThread())也不起作用
为什么?
发布于 2020-08-15 02:44:05
程序在代码有时间执行之前就退出了。尝试在subscribe之后使用睡眠或put in语句
fun main() {
Single.just("faefw")
.subscribeOn(Schedulers.io())
.map {
println("map in thread ${Thread.currentThread().name}")
}
.flatMap {
return@flatMap Single.just(231).map {
println("map in thread ${Thread.currentThread().name}")
return@map it
}
}
.subscribe({
println(it)
}, {
println(it)
})
println("just subscribed in last statement!")
Thread.sleep(500)
println("exiting main thread...")
}使用trampoline时,输出为
map in thread main
map in thread main
231
just subscribed in last statement!
exiting main thread...对于在不同线程中执行“工作”的其他调度器(如.io()和.computation()),输出将如下所示:
just subscribed in last statement!
map in thread RxComputationThreadPool-1
map in thread RxComputationThreadPool-1
231
exiting main thread...PS。您可以将io()调度器视为无界线程池,将computation()视为有界线程池。
https://stackoverflow.com/questions/63417737
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