基本上,我想得到两个计数。第一个计数是记录数。第二个计数是包含数据的记录数。这两个计数来自名为调查的表,该表并不包含所有州的名称。因此,我将它与另一个表UsState连接起来,以获得所有州的名称。我把语法放在一起,但我得到了一个错误。
SELECT
Name as State,
count (*)from NamrsFrozen2017.Investigation2017 where FiscalYear = 2017 AND StateName in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))[Report Date Records],
count (*) from NamrsFrozen2017.Investigation2017 WHERE FiscalYear = 2017 AND ReportDate != '' AND StateName in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))[Report Date Records with Data]
From
(SELECT DISTINCT Name FROM NamrsFullDw.UsState) s
LEFT JOIN NamrsFrozen2017.Investigation2017 c ON s.Name = c.StateName AND c.FiscalYear = 2017
GROUP BY Name
Order by Name发布于 2019-04-11 23:03:39
一些相关子查询会对您有所帮助。它们看起来像内联selects,但使用对内联查询外部的表的引用。如下所示:
SELECT
Name as State,
(SELECT COUNT(*)
FROM NamrsFrozen2017.Investigation2017
--I would think you want to view count of records for the current state, and not ALL states
-- and not ALL states. So filter like this:
WHERE FiscalYear = 2017 AND StateName = s.Name -- <-Correlated
--Don't need a full list, like you had before
-- (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))
) AS [Report Date Records],
(SELECT COUNT(*)
FROM NamrsFrozen2017.Investigation2017
WHERE FiscalYear = 2017 AND StateName = s.Name -- <- correlated
AND ReportDate != '' --or maybe ReportDate IS NOT NULL
--Don't need to query the full table after correlating this to your FROM clause
-- in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))
) AS [Report Date Records with Data]
FROM
(SELECT DISTINCT Name FROM NamrsFullDw.UsState) s
LEFT JOIN NamrsFrozen2017.Investigation2017 c
ON s.Name = c.StateName AND c.FiscalYear = 2017
GROUP BY s.Name
ORDER BY s.Name这可能会优化得更多,但我不熟悉您的数据,也不清楚您到底想要用原始查询完成什么。
发布于 2019-04-11 23:38:12
评论太长了。
出现语法错误是因为内联子查询的格式不正确。不能从COUNT(*)函数开始;它们都需要是完全形式的SELECT语句。然后每一个都需要用括号括起来。
这就是您的查询应该是什么样子。
SELECT
Name AS State
,(
SELECT
COUNT(*)
FROM
NamrsFrozen2017.Investigation2017
WHERE
FiscalYear = 2017
AND StateName IN
(
SELECT DISTINCT StateName
FROM NamrsFrozen2017.Investigation2017
WHERE ReportDate <> ''
)
) AS [Report Date Records]
,(
SELECT
COUNT(*)
FROM
NamrsFrozen2017.Investigation2017
WHERE
FiscalYear = 2017
AND ReportDate != ''
AND StateName IN
(
SELECT DISTINCT StateName
FROM NamrsFrozen2017.Investigation2017
WHERE (NOT ReportDate = '')
)
) AS [Report Date Records with Data]
FROM
(SELECT DISTINCT Name FROM NamrsFullDw.UsState) AS s
LEFT JOIN
NamrsFrozen2017.Investigation2017 AS c
ON
s.Name = c.StateName
AND c.FiscalYear = 2017
GROUP BY
Name
ORDER BY
Name;这里还有一个次要问题,那就是这个查询是否会做您期望它做的事情。根据Larnu在评论中的观点,聚合函数在不同的环境中以不同的方式处理NULL。但是,如果没有样本数据进行测试,我就不能断定这个正常运行的查询版本是否会返回您想要的结果。
https://stackoverflow.com/questions/55634566
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