我根据下面第一项的值通过对象数组进行分组:
const json2 = [{"value":"value1","metric":1},{"value":"value1","metric":2},{"value":"value3","metric":0},{"value":"value2","metric":4},{"value":"value3","metric":1},{"value":"value3","metric":1}];
const result2 = [...json2.reduce((r, o) => {
const key = o.value;
const item = r.get(key) || Object.assign({}, o, {
metric: 0,
});
item.metric += o.metric;
return r.set(key, item);
}, new Map).values()];
console.log(result2);
但是,当我有一个对象数组时,我很难做到同样的事情,如下所示:
[[{"value":"value1","formattedValue":"value1"},{"value":2831.8,"formattedValue":"283,180.00 %"}],[{"value":"value1","formattedValue":"value1"},{"value":349.1111111111111,"formattedValue":"34,911.11 %"}],[{"value":"value2","formattedValue":"value2"},{"value":3.3703703703703702,"formattedValue":"337.04 %"}]]因此,与以前的JSON相比,不同之处在于:
{"value":"value1","metric":1}现在是:
[{"value":"value1","formattedValue":"value1"},{"value":"1.0","formattedValue":100.00 %}]一种解决方案是操作第二个查询,使其看起来像第一个查询,但在本例中,我想让它与上面的函数一起工作。
想要的结果是:
[[{"value":"value1","formattedValue":"value1"},{"value":3180.91111111,"formattedValue":"318091.11 %"}],[{"value":"value2","formattedValue":"value2"},{"value":3.3703703703703702,"formattedValue":"337.04 %"}]]发布于 2019-09-05 19:29:30
您可以通过解构获取键/值并更新结果集。
var data = [[{ value: "value1", formattedValue: "value1" }, { value: 2831.8, formattedValue: "283,180.00 %" }], [{ value: "value1", formattedValue: "value1" }, { value: 349.1111111111111, formattedValue: "34,911.11 %" }], [{ value: "value2", formattedValue: "value2" }, { value: 3.3703703703703702, formattedValue: "337.04 %" }]],
result = Array.from(
data
.reduce((m, a) => {
var [{ value: key }, { value }] = a,
target = m.get(key);
if (!target) return m.set(key, JSON.parse(JSON.stringify(a)));
target[1].value += value;
target[1].formattedValue = `${(target[1].value * 100).toFixed(2) } %`;
return m;
}, new Map)
.values()
);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }
https://stackoverflow.com/questions/57804202
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