python基于模式拆分长输出字符串(无分隔符)

Question

我是python的新手，我试着用(PyPDF2)来阅读PDF地图。我得到了这个作为输出Sample output of pdf map as text。我想从这个输出中提取某个模式与RIY-DIRAHH-015524.49121946.651068匹配的数据。我只需要那些只有这个模式的值。图案的长度在30-34之间变化。已针对RIY-DIRAHH-0155修复，而更改仅在LAT/LONG 24.49121946.651068中发生。Complete output of PDF MAP。

请帮助提取/拆分特定值(匹配模式)。如果有任何其他解决方案可用于阅读PDF地图。敬请指教。提前谢谢。

import re
x='result of PDF map'[image1]
result = re.search('\w{3}-\w{6}-\d*.\d*.\d*',x)
#output
['', '', '', '', '']

Sample Image of map。

Answer 1

下面是一个适用于您的正则表达式：

re.findall(r"RIY-[A-Z]{6}-\d{6}\.\d{8}\.\d{5,7}", text)

结果是：

 'RIY-OUHOMH-100224.53476846.650127',
 'RIY-OUHOMH-100324.53282546.65039',
 'RIY-OUHOMH-100424.53224446.651758',
 'RIY-OUHOHH-100724.52902946.653571',
 'RIY-OUHOHH-100624.53007146.651934',
 'RIY-OUHOHH-100524.53178646.65279',
 'RIY-OUHOMH-100124.53597246.649456',
 'RIY-DIRAHH-015124.49540746.641877',
 'RIY-DIRAHH-015224.49410546.644253',
 'RIY-DIRAHH-015324.49267846.646789',
 'RIY-DIRAHH-015424.49144946.649107',
 'RIY-DIRAHH-015524.49121946.651068',
 'RIY-DIRAHH-015624.49343446.652505',
 'RIY-DIRAHH-015724.49563146.653924',
 ...

编辑

要将这段代码分成几列，整个代码应该是：

out = re.findall(r"RIY-[A-Z]{6}-\d{6}\.\d{6,8}\.\d{5,7}", text) 
df = pd.DataFrame(out, columns = ["RIY"]) 

df["col1"] = df.RIY.str[0:15]
df["col2"] = df.RIY.str[15:24]
df["col3"] = df.RIY.str[24:]

然后，df将如下所示：

                                 RIY             col1       col2       col3
0  RIY-OUHOMH-100224.53476846.650127  RIY-OUHOMH-1002  24.534768  46.650127
1   RIY-OUHOMH-100324.53282546.65039  RIY-OUHOMH-1003  24.532825   46.65039
2  RIY-OUHOMH-100424.53224446.651758  RIY-OUHOMH-1004  24.532244  46.651758
3  RIY-OUHOHH-100724.52902946.653571  RIY-OUHOHH-1007  24.529029  46.653571
4  RIY-OUHOHH-100624.53007146.651934  RIY-OUHOHH-1006  24.530071  46.651934