file = open(file = r'moto.txt')
bscAlertLines = file.readlines()
for alertLine in bscAlertLines:
if "MAINS_FAIL (1)" in alertLine:
inxAlert = bscAlertLines.index(alertLine)
print(inxAlert)
alertString = alertLine.split()
print(alertString)输出如下所示:
86
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '02-15-2020', 'MAINS_FAIL', '(1)']
194
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-24-2020', 'MAINS_FAIL', '(1)']
194
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-24-2020', 'MAINS_FAIL', '(1)']
243
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-22-2020', 'MAINS_FAIL', '(1)']
262
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '02-22-2020', 'MAINS_FAIL', '(1)']
194
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-24-2020', 'MAINS_FAIL', '(1)']
194
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-24-2020', 'MAINS_FAIL', '(1)']
194
['EAS', '0', '0', '0', '17', 'FMIC', 'Untagged', '03-24-2020', 'MAINS_FAIL', '(1)']在这种情况下,索引194是重复的(因为列表的内容相似),但在文本文件中,它位于不同的索引,如285,322,400。我如何检索这些。如何检索文件中的原始索引
发布于 2020-03-25 14:44:00
index函数总是返回alertLine出现的第一个索引,而enumerate函数会帮您一个忙:
with open('moto.txt','r') as f:
for i,line in enumerate(f):
if "MAINS_FAIL (1)" in line:
print(i,line.split(),sep='\n')发布于 2020-03-25 15:35:02
简单地说,index()方法在列表中查找给定的元素并返回其位置。
如果同一元素多次出现,该方法将返回该元素第一次出现的索引。
代码:
file = open(file = r'moto.txt')
index = 0
bscAlertLines = file.readlines()
for alertLine in bscAlertLines:
index++
if "MAINS_FAIL (1)" in alertLine:
print(index-1)
alertString = alertLine.split()
print(alertString)发布于 2020-03-25 14:45:08
from collections import defaultdict
arr = [
["a", 15, "x"],
["b", 15, "x"],
["a", 15, "x"],
["a", 10, "y"],
["b", 15, "x"],
["b", 15, "y"],
["a", 10, "y"]
]
hash_map = defaultdict(list)
for i, list_el in enumerate(arr):
el = tuple(list_el)
hash_map[el].append(i)
print(hash_map)这提供了:
{
('a', 15, 'x'): [0, 2],
('b', 15, 'x'): [1, 4],
('a', 10, 'y'): [3, 6],
('b', 15, 'y'): [5]
}因为列表是可变的,并且不能用作字典中的键,所以我将它们转换为元组,以便能够将其存储在字典中。
https://stackoverflow.com/questions/60843840
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