AudioKit快速平移

Question

我目前正在audioKit的帮助下开发一个应用程序。我正在尝试平移音频，以便它一次只在一只耳朵中播放。有什么想法可能是错误的吗？

声音正在播放，但它在两只耳朵中同时播放。

func createTone(freq: Double, dB: Int, isLeftEar: Bool){
        currentFreq = Int(freq)
        currentdB = dB
        isAudioOn = true
        osciliator.frequency = freq
        osciliator.amplitude = calculateVolume(dB: dB)
        osciliator.rampDuration = 0.25
        let leftPan = AKPanner(osciliator, pan: -1)
        let rightPan = AKPanner(osciliator, pan: 1)
        if(isLeftEar){
            AudioKit.AKManager.output = leftPan
            
        }else{
            
            AudioKit.AKManager.output = rightPan
        }
        do{
            try AudioKit.AKManager.start()
        }catch{
            print("could not start AudioKit.")
        }
        
        if isLeftEar {
            leftPan.start()
        }else{
            rightPan.start()
        }
        
        osciliator.start()
        sleep(2)
        
        do{
            try AudioKit.AKManager.stop()}
        catch{
            print("AudioKit could not stop")
        }

Answer 1

通常，节点是在类级别声明的，而不是局部变量。所以你会有类似这样的东西：

class ViewController: UIViewController {

var panner: AKPanner!

func createTone(freq: Double, dB: Int, isLeftEar: Bool){
    // ...

    panner = AKPanner(oscillator, pan: (isLeftEar) ? -1 : 1)
    // ...
}

此外，永远不应该在主线程中调用sleep。您应该使用DispatchQueue.main.asyncAfter

DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
    do{
        try AKManager.stop()}
    catch{
        print("AudioKit could not stop")
    }
}

更新

我用AudioKit 4.10.1测试了以下代码，它确实正确地平移到了左声道。

var panner: AKPanner!
var oscillator: AKOscillator!

func createTone(){
    oscillator = AKOscillator()
    panner = AKPanner(oscillator, pan: -1)
    AKManager.output = panner
    do{
        try AudioKit.AKManager.start()
    }catch{
        print("could not start AudioKit.")
    }
    
    panner.start()
    oscillator.start()
    
    DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + 20.0) {
        do {
            try AudioKit.AKManager.stop()
        } catch {
            print("AudioKit could not stop")
        }
    }
}